Let 1993 = time 0 = 0.
Let 1999 = time 6 = 6
Let 2012 = time 19 = 19
So, a = 171 (million). First solve for k.
176 = 171 e^k6
176/171 = e^(k*6)
ln (176/171) = 6k
k = 1/6 ln (176/171)
So, in 2012 we have: P(19) = 171 e^(19k), where k = 1/6 ln (176/171)
Hope this helped!
On a cos(x) graph, the minimum y-value is always -1. Since you are adding 5 to -1, the minimum values is 4.
Answer:
6,3,-3, and -6
Step-by-step explanation:
You just replace y with the given numbers, then solve for x
