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Anna35 [415]
3 years ago
7

Suppose someone tells you that she has a triangle with sides having lengths 3.5, 4.5 and 5.5 yards. Is this a right triangle?

Mathematics
2 answers:
Katarina [22]3 years ago
5 0
You can solve by using Pythagoras theorem.
Let the longest side be c.
a^2 + b^2 = c^2
If this holds, it is a right angle.

But, 3.5^2 + 4.5^2 is not equal to 5.5^2.
Sloan [31]3 years ago
3 0
I don't know.
Let's find out.
If it IS a right triangle, then . . .

    (square of the shortest side)
plus
    (square of the medium side)
adds up to
    
(square of the longest side).

Shortest side = 3.5 .  Its square is  (3.5)²  =  12.25
Medium side = 4.5 .  Its square is  (4.5)²   =  20.25
(square of the shortest side) + (square of the medium side) =  32.5 .

Longest side = 5.5 .  Its square is  (5.5)²   =  30.25 .

  30.25  is NOT equal to  32.5 .

  So this is NOT a right triangle.

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Step-by-step explanation:

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4 0
3 years ago
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Find the area of the shape shown below.
rusak2 [61]

Answer:

12.5

Step-by-step explanation:

So this is basically a rectangle. You make the 2 triangles a square.

2.5x2.5=6.25

6.25x2=12.5

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3 years ago
If y=3x + 2, find the value of y when x= -2
Luda [366]
Y=3x + 2
This form represents an affine function, graphically represented by a straight line (y = mx + b)
All you need to do is replace "x" by -2 in 3x + 2, and you'll find the value of y.

y = 3x + 2
y = 3 * (-2) + 2
y = -6 + 2
y = -4

So when x = -2, y = -4. Graphically, x and y represents the coordinates of a point belonging to the line of y=3x+2 (I represented the graphic and the bottom of the answer)

Hope this Helps! :)

4 0
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Step-by-step explanation:

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3 years ago
Solve the inequality. Graph the solution set. 26 +6b&gt;2(3b+4)
Novosadov [1.4K]

Answer:

True for all b

Interval notation; (-∞, ∞)

Step-by-step explanation:

We have been given the following inequality;

26+6b>2(3b+4)

The first step is to open the brackets on the right hand side;

26+6b>6b+8

26-8>6b-6b

18>0

Since 18 is actually greater than 0, the solution set to the inequality is;

True for all b.

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