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Anna35 [415]
3 years ago
7

Suppose someone tells you that she has a triangle with sides having lengths 3.5, 4.5 and 5.5 yards. Is this a right triangle?

Mathematics
2 answers:
Katarina [22]3 years ago
5 0
You can solve by using Pythagoras theorem.
Let the longest side be c.
a^2 + b^2 = c^2
If this holds, it is a right angle.

But, 3.5^2 + 4.5^2 is not equal to 5.5^2.
Sloan [31]3 years ago
3 0
I don't know.
Let's find out.
If it IS a right triangle, then . . .

    (square of the shortest side)
plus
    (square of the medium side)
adds up to
    
(square of the longest side).

Shortest side = 3.5 .  Its square is  (3.5)²  =  12.25
Medium side = 4.5 .  Its square is  (4.5)²   =  20.25
(square of the shortest side) + (square of the medium side) =  32.5 .

Longest side = 5.5 .  Its square is  (5.5)²   =  30.25 .

  30.25  is NOT equal to  32.5 .

  So this is NOT a right triangle.

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xeze [42]

Answer:

19

Step-by-step explanation:

2d + 3

d = 8

2(8) + 3

multiply 2 and 8

16 + 3

add 16 and 3

= 19

4 0
2 years ago
What is Derricka's goal, in miles, for the total distance she will swim on Monday, Tuesday, and Wednesday? Show your work.
denpristay [2]

Answer:

there is no backgroung information?

Step-by-step explanation:

3 0
3 years ago
What is the greatest common factor of 44c^5, 22c^3 and 11c^4
Alexxandr [17]

\text{ GCF of } 44c^5, 22c^3 , 11c^4 \text{ is } 11c^3

<em><u>Solution:</u></em>

Given that, we have to find the greatest common factor of 44c^5, 22c^3 , 11c^4

The greatest number that is a factor of two (or more) other numbers.

When we find all the factors of two or more numbers, and some factors are the same ("common"), then the largest of those common factors is the Greatest Common Factor

\underline{\text{ GCF of } 44c^5, 22c^3 , 11c^4 :}

First find the GCF of numbers and then find the GCF of variables and then multiply them together

<em><u>Step 1: GCF of 44, 22 and 11</u></em>

The factors of 11 are: 1, 11

The factors of 22 are: 1, 2, 11, 22

The factors of 44 are: 1, 2, 4, 11, 22, 44

11 is the greatest factor that is common in above three list

Then the greatest common factor is 11

\text{ Step 2: GCF of }c^5, c^3 , c^4

c^5 = c^3 \times c^2\\\\c^3 = c^2 \times c^1 \text{ or } c^3\\\\c^4 = c^3 \times c^1

Thus the greatest common factor is c^3

Step 3: Multiply the GCF of 44, 22, 11 and GCF of c^5, c^3 , c^4

\text{ GCF of } 44c^5, 22c^3 , 11c^4 = 11 \times c^3 = 11c^3

Thus \text{ GCF of } 44c^5, 22c^3 , 11c^4 \text{ is } 11c^3

8 0
3 years ago
Please answer the question in the photo:
Vika [28.1K]

Answer:

\fbox{8x+36}

Step-by-step explanation:

1. Use the distributive property to write the problem without parentheses. The distributive property says that you can multiply a number next to parentheses by all the numbers inside parentheses. The picture below explains.

4(2x+9)=\\\\(4*2x)+(4*9)=\\\\4(2x+9)= 8x+36

Therefore, your answer is

\fbox{8x+36}

6 0
3 years ago
If jenny has 1,490÷6 how will you solve it.
puteri [66]
It's 248.3333 (but with the 3s repeating)
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