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Sloan [31]
3 years ago
9

What is the absolute deviation for 62 in the data set?

Mathematics
2 answers:
katrin2010 [14]3 years ago
7 0
I think the accurate answer to this question, based from the sources,  is 5. Deviation, in statistics, describes how the data set is spreaded from each other.  Thank you for your question. Please don't hesitate to ask in Brainly your queries
Aleksandr [31]3 years ago
4 0

Answer:

0

Step-by-step explanation:

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The population of Rock Springs is growing at a constant rate. The expression represents the increase in population in x years. 4
shusha [124]
The expression is given such as:
45, 200 + 1900x

We are asked to solve for the initial production, which means we have x = 0
The solution is shown below:
45, 200 + 1900*0
= 45,200 +0
=45, 200

The answer is letter "C" 45, 000.
8 0
3 years ago
The equation p(t) = 1.e represents a
zvonat [6]

Answer:

(b), (d) and (e)

Step-by-step explanation:

Given

p(t) = 1 * e^t

See attachment for y = p(t)

Required

Select true statements from the given options

(a) \ln(30) = days the bacteria reaches 30000

We have:

p(t) = 1 * e^t

In this case:

t = \ln(30) and p(t) = 30000

So, we have:

30000 = 1 * e^{\ln(30)}

30000 = e^{\ln(30)}

Using a calculator, we have:

e^{\ln(30)} = 30

So:

30000 = 30

The above equation is false.

(a) is not true

(b) The graph shows that \ln(20) \approx 3

We have:

p(t) = 1 * e^t

Let t = 3

So;

p(3) = 1 * e^3

From the graph, p(3) = 20

So:

20 = 1 * e^3

20 = e^3

Take natural logarithm of both sides

\ln(20) = \ln(e^3)

This gives:

\ln(20) = 3

(b) is true

(c) \ln(t) = y is the logarithm form of y = e^t

We have:

y = e^t

Take natural logarithm of both sides

\ln(y) = \ln(e^t)

This gives:

\ln(y) = t

\ln(y) = t  \ne \ln(t) = y

(c) is false

(d) e^4 > 50 and  \ln(50) < 4

From the graph, we have:

e^4 = 54 --- rough readings

This implies that:

e^4 > 50 is true

Because 54 > 50

Take natural logarithm of both sides

\ln(54) > \ln(50)

Rewrite as:

\ln(50) < \ln(54)

We have:

e^4 = 54

Take natural logarithm of both sides

\ln(e^4) = \ln(54)

4 = \ln(54)

\ln(54) = 4

Substitute \ln(54) = 4 in \ln(50) < \ln(54)

\ln(50) < 4

(d) is true

(e) The graph shows that 10 \approx \ln(2.3)

We have:

p(t) = 1 * e^t

Let t = 2.3

So;

p(2.3) = 1 * e^{2.3}

From the graph,

p(2.3) = 10 ---- rough readings

So:

10 = 1 * e^{2.3}

10 = e^{2.3}

Take natural logarithm of both sides

\ln(10) = \ln(e^{2.3})

This gives:

\ln(10) = 2.3

(e) is true

4 0
3 years ago
The table below represents an exponential function what is the common ratio
Greeley [361]

Solution:

Given:

A table representing an exponential function.

The x-values represent the terms, while the y-values represent the numbers.

The common ratio is gotten from the numbers (y-values).

The formula for common ratio is given by;

\begin{gathered} r=\frac{present\text{ term}}{preceed\text{ ing term}} \\  \\ \text{Hence,} \\ r=\frac{108}{36}=\frac{36}{12}=\frac{12}{4}=\frac{4}{1.33\ldots}=\frac{1.33\ldots.}{0.44\ldots} \\ r=3 \end{gathered}

Therefore, the common ratio is 3.

3 0
2 years ago
The radius of the cone is 1.25 inches, and its height is 2.75 inches. If the diameter of the bubble gum ball is 0.5 inches, what
nasty-shy [4]
<h2>Explanation:</h2><h2></h2>

The volume of a cone can be found as:

V=\frac{1}{3}\pi r^2 h \\ \\ \\ Where: \\ \\ V:Volume \\ \\ r:radius \ of \ base \\ \\ h:height

Given the radius and height, we can find the volume of the cone:

V=\frac{1}{3}\pi r^2 h \\ \\ V=\frac{1}{3}\pi (1.25)^2(2.75) \\ \\ V=\frac{1}{3}\pi(1.5625)(2.75) \\ \\ V\approx 4.5in^3

The volume of a sphere is:

V=\frac{4}{3}\pi r^3 \\ \\ \text{Each gum ball has a diameter of 0.5in, so the radius is:} \\ \\ r=\frac{0.5}{2}=0.25in

So, for each gum ball the volume is:

V=\frac{4}{3}\pi r^3 \\ \\ V=\frac{4}{3}\pi (0.25)^3 \\ \\ V=0.065in^3

Therefore, the he closest approximation of the volume of the cone that can be filled with flavored ice is:

4.5-0.065=4.43in^3

Conclusion: The volume of the cone that can be filled with flavored ice is 4.43 cubic inches.

3 0
4 years ago
Logan took out $23,400 in student loans to attend college at a compound interest rate of 5%. He deferred payments for two years.
blagie [28]

Answer:

$25,740

Step-by-step explanation:

First, converting R percent to r a decimal

r = R/100 = 5%/100 = 0.05 per year,

then, solving our equation

I = 23400 × 0.05 × 2 = 2340

I = $ 2,340.00

The simple interest accumulated

on a principal of $ 23,400.00

at a rate of 5% per year

for 2 years is $ 2,340.00.

8 0
3 years ago
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