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blondinia [14]
4 years ago
6

a student must have an average on five test that is greater than it equal to 80% but less than 90% to receive a final grade of B

. Devon's greades on the first four test were 78% 62% 91% and 80% what range if grades on the fifth test would give him a B in the course? ( assuming the highest grade is 100%)
Mathematics
1 answer:
Bad White [126]4 years ago
6 0

Answer:

  89–100

Step-by-step explanation:

Let x represent the grade on the fifth test. The average for 5 tests wants to be between 80 and 90, so we have ...

  80 ≤ (78 +62 +91 +80 +x)/5 ≤ 90

Multiplying by 5 gives

  400 ≤ 311 +x ≤ 450

Subtracting 311 gives the range for the fifth test grade.

  89 ≤ x ≤ 139

Since the maximum available score is 100, the range on the 5th test for an overall B grade is ...

  89 ≤ x ≤ 100 . . . . where x is the grade on the 5th test

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Step 1 : Find how many grams 1 jar of paprika weighs.
We know 7 jars of paprika has a weight of 210 grams, so we know that 1 jar of paprika weighs 30 grams.
Step 2 : Find the weight of 4 packets of sage.
To do this let’s first multiply the weight of 1 paprika jar by 3 (30 times 3) which is 90 grams. So out of the 290 grams total,
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Step 3 : Find the weight of each packet of sage.
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Step 4 : add them together.
2(30) + 2(50) = 60 + 100
60 + 100 = 160
Therefore the total weight of 2 jars of paprika and 2 packets of sage is 160 grams.
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