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blondinia [14]
3 years ago
6

a student must have an average on five test that is greater than it equal to 80% but less than 90% to receive a final grade of B

. Devon's greades on the first four test were 78% 62% 91% and 80% what range if grades on the fifth test would give him a B in the course? ( assuming the highest grade is 100%)
Mathematics
1 answer:
Bad White [126]3 years ago
6 0

Answer:

  89–100

Step-by-step explanation:

Let x represent the grade on the fifth test. The average for 5 tests wants to be between 80 and 90, so we have ...

  80 ≤ (78 +62 +91 +80 +x)/5 ≤ 90

Multiplying by 5 gives

  400 ≤ 311 +x ≤ 450

Subtracting 311 gives the range for the fifth test grade.

  89 ≤ x ≤ 139

Since the maximum available score is 100, the range on the 5th test for an overall B grade is ...

  89 ≤ x ≤ 100 . . . . where x is the grade on the 5th test

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Step-by-step explanation:

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3 years ago
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A diagonal of a cube measures
Gennadij [26K]

Answer: 7cm

Step-by-step explanation:

Use pythagorean theorum:

Variables:

Let the edge = A

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A^2 = [sqrt(150)]^2 - 10^2

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2 years ago
1<br> —<br> 3<br> (9x + 3) = 3x + 1
Hatshy [7]

Answer: x = -0.3

Step-by-step explanation:

<u>Given expression</u>

1 - 3 (9x + 3) = 3x + 1

<u>Expand parentheses and apply the distributive property</u>

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<u>Combine like terms</u>

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(-30)x / (-30) = 9 / (-30)

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\boxed{x=-0.3}

Hope this helps!! :)

Please let me know if you have any questions

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3 years ago
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