Answer:
(5) The perpendicular height of the triangle is 8.48 mm.
(6) The 1184.86 cm far up the wall the ladder reach.
Step-by-step explanation:
Part (5):
When a perpendicular is drawn in an isosceles triangle then the perpendicular divided the base into 2 equal parts.
The figures is shown below.
In ΔABC,
CB = 6 mm
So,
CD = BD = 3 mm
Now calculating the perpendicular height of the triangle.
Using Pythagoras theorem in ΔADC:

Thus, the perpendicular height of the triangle is 8.48 mm.
Part (6):
The figure is shown below.
Converting meter to centimeter:
1 m = 100 cm
So,
12 m = 1200 cm
Using Pythagoras theorem in ΔXYZ:

Thus, 1184.86 cm far up the wall the ladder reach.
there is no graph here to answer this
In a trapezoid, two opposite sides are parallel and are called bases.
In this trapezoid, the top and bottom sides are parallel and are the bases.
The right side that intersects both bases is a transversal.
When parallel lines are cut by a transversal, same-side interior angles are supplementary. The measures of supplementary angles add to 180 deg.
x + 72 = 180
x = 180 - 72
x = 108 deg