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Aleksandr [31]
2 years ago
8

Sue uses the expression (8×3,000)+(8×200)+(8×9) to help solve a multiplication problem. What is sues multiplication problem?

Mathematics
1 answer:
-BARSIC- [3]2 years ago
7 0
Her multiplication problem might be 8x3,209
You might be interested in
a chord of 12cm long of 8cm is away from the of the circle what is the lenght of the chord which is 6cm away from the centre
lana66690 [7]

Answer:

The length of the chord is 16 cm

Step-by-step explanation:

Mathematically, a line from the center of the circle to a chord divides the chord into 2 equal portions

From the first part of the question, we can get the radius of the circle

The radius form the hypotenuse, the two-portions of the chord (12/2 = 6 cm) and the distance from the center to the chord forms the other side of the triangle

Thus, by Pythagoras’ theorem; the square of the hypotenuse equals the sum of the squares of the two other sides

Thus,

r^2 = 8^2 + 6^2

r^2= 64 + 36

r^2 = 100

r = 10 cm

Now, we want to get a chord length which is 6 cm away from the circle center

let the half-portion that forms the right triangle be c

Using Pythagoras’ theorem;

10^2 = 6^2 + c^2

c^2 = 100-36

c^2 = 64

c = 8

The full

length of the chord is 2 * 8 = 16 cm

5 0
3 years ago
Quadrilateral FGHJ is dilated according to the rule DO,(x,y) to create the image quadrilateral F'G'H'J', which is not shown. Wha
Simora [160]

Answer: it’s -2,-4


Step-by-step explanation: since the dilation rule is 2/3 we take 2/3 of all the numbers. For example we took two thirds of -3 to get -2.


6 0
3 years ago
The relationship between the length of one side of the Square, eggs, and the perimeter of the Square, why, can be represented in
oee [108]

Answer:

The points with coordinates (x, y) that are on the line of the equation of the line relationship between the side of a square, x and the perimeter, y include;

(1, 4), (2, 8), (3, 12) ....(n, 4·n).

Where n is a positive number.

Step-by-step explanation:

The formula to determine the length of the perimeter of a square is,

Length of the perimeter of a square = Length of a side of the square multiplied by 4.

That is Perimeter of square = Side of square × 4

The relationship between the length of one side of a square and the perimeter of the square can be represented by the equation

y = 4×d which is a straight line with a slope of 4 passing through the origin

Points o the line include

(1, 4), (2, 8), (3, 12), etc.

The x and y coordinates take the form

(x, 4·x)

5 0
3 years ago
How to solve it I am very confused
a_sh-v [17]

Answer:

Answer:

53/12+28/3=13/34

Solution with Steps

53/12+28/3=?

The fractions have unlike denominators. First, find the Least Common Denominator and rewrite the fractions with the common denominator.

LCD(53/12, 28/3) = 12

Multiply both the numerator and denominator of each fraction by the number that makes its denominator equal the LCD. This is basically multiplying each fraction by 1.

(53/12×1/1)+(28/3×4/4)=?

Complete the multiplication and the equation becomes

53/12+112/12=?

The two fractions now have like denominators so you can add the numerators.

Then:

53+112/12=165/12

This fraction can be reduced by dividing both the numerator and denominator by the Greatest Common Factor of 165 and 12 using

GCF(165,12) = 3

165÷3/12÷3=55/4

The fraction

55/4

is the same as

55÷4

Convert to a mixed number using

long division for 55 ÷ 4 = 13R3, so

55/4=13 3/4

Therefore:

53/12+28/3=13/34

Solution by Formulas

Apply the fractions formula for addition, to

53/12+28/3

Reduce by dividing both the numerator and denominator by the Greatest Common Factor GCF(495,36) = 9

49/5÷93/6÷9=554

Convert to a mixed number using

long division for 55 ÷ 4 = 13 R3, so

554=1334

Therefore:

53/12+28/3=13 3/4

So I Believe 13 3/4  or 55/4

I hope this isn't wrong.

6 0
3 years ago
Hexagon DEFGHI is translated on the coordinate plane below to create hexagon D'E'F'G'H'I': Hexagon DEFGHI and Hexagon D prime E
liraira [26]
D (2, 5) > (-6, -2)
E (5, 5) > (-3, -2)
F (6, 3) > (-2, -4)
G (5, 1) > (-3, -6)
H (2, 1) > (-6, -6)
I (1, 3) > (-7, -4)

Looking at the transitions all side by side, you could tell they all turn negative so one can assume the transition is a negative.

Therefore, the rule would be:

(x-8, y-7)
3 0
2 years ago
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