Answer:
0 is the answer. I think.
i) u + 3 V
1 by 2 + 3 *minus 2
1 by 2 -6
1 - 12 by 2
- 11 by 2
ii) - 3 * 1 by 2 + 2 * -2 + 3 by 4
minus 19 by 4
Answer:
See below.
Step-by-step explanation:
Fifth root of 243 = 3,
Suppose r( cos Ф + i sinФ) is the fifth root of 243(cos 240 + i sin 240),
then r^5( cos Ф + i sin Ф )^5 = 243(cos 240 + i sin 240).
Equating equal parts and using de Moivre's theorem:
r^5 =243 and cos 5Ф + i sin 5Ф = cos 240 + i sin 240
r = 3 and 5Ф = 240 +360p so Ф = 48 + 72p
So Ф = 48, 120, 192, 264, 336 for 48 ≤ Ф < 360
So there are 5 distinct solutions given by:
3(cos 48 + i sin 48),
3(cos 120 + i sin 120),
3(cos 192 + i sin 192),
3(cos 264 + i sin 264),
3(cos 336 + i sin 336).. (Answer).
The answer is:
The pineapples Mr. Lester sells are $2.40
Answer:
6^2 + 5^2 = d^2
Step-by-step explanation:
I hope this helps!!
