Answer:
7. r = -5
8. x = -1
General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
Equality Properties
Step-by-step explanation:
<u>Step 1: Define</u>
r + 2 - 8r = -3 - 8r
<u>Step 2: Solve for </u><em><u>r</u></em>
- Combine like terms: -7r + 2 = -3 - 8r
- Add 8r to both sides: r + 2 = -3
- Subtract 2 on both sides: r = -5
<u>Step 3: Check</u>
<em>Plug in r into the original equation to verify it's a solution.</em>
- Substitute in <em>r</em>: -5 + 2 - 8(-5) = -3 - 8(-5)
- Multiply: -5 + 2 + 40 = -3 + 40
- Add: -3 + 40 = -3 + 40
- Add: 37 = 37
Here we see that 37 does indeed equal 37.
∴ r = -5 is a solution of the equation.
<u>Step 4: Define equation</u>
-4x = x + 5
<u>Step 5: Solve for </u><em><u>x</u></em>
- Subtract <em>x</em> on both sides: -5x = 5
- Divide -5 on both sides: x = -1
<u>Step 6: Check</u>
<em>Plug in x into the original equation to verify it's a solution.</em>
- Substitute in <em>x</em>: -4(-1) = -1 + 5
- Multiply: 4 = -1 + 5
- Add: 4 = 4
Here we see that 4 does indeed equal 4.
∴ x = -1 is a solution of the equation.
Answer:
1. $6.20
2. Samantha has $79, she decides to go to the mall and buys 6 dresses that are $7 each. She thinks that she might not have enough money so she returns 2 dresses. She then finds out that she has more than enough so she buys a candy bar for $5. How much money does she have left?
Sam has $79, she buys 6 dresses that cost $7 each. She returns 2 dresses and then buys a candy bar for $5. How much money does she have left?
Step-by-step explanation:
1. you can write an equation to represent the word problem
20-(2.10+0.9x)
20-(2.10+0.9(13)
20-(2.10+11.7)
20-(13.8)
6.2
He has 11 quarters, 9 dimes, and 55 nickels.
11x.25=2.75
9x.1=.9
55x.05=2.75
2.75+2.75+.9=6.4
Answer:
11
Step-by-step explanation:
6 2/8 = 6 1/4
6 1/4 + 4 3/4 = 10 4/4
11
Answer:
A
Step-by-step explanation:
The picture below illustrates a hyperbola.
The intersecting plane does not pass through the vertex of a right circular cone (the vertex of the cone is the point where two nappes meet).
As you can see from the diagram, the plane intersects both nappes of a right circular cone.
Hence, correct option is option A: The plane does not pass through the vertex and intersects both nappes of a right circular cone.