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Monica [59]
3 years ago
5

What type of transformation maps triangle QRS to triangle Q'R'S why?

Mathematics
1 answer:
velikii [3]3 years ago
3 0

Answer:

Step-by-step explanation:

rotation

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Where should the point P be chosen on line segment AB so as to maximize the angle θ? (Assume a = 4 units, b = 5 units, and c = 9
taurus [48]
From the figure, let the distance of point P from point A on line segment AB be x and let the angle opposite side a be M and the angle opposite side c be N.

Using pythagoras theorem,
\tan M= \frac{a}{b-x} \\ \\ M=\tan^{-1}\left(\frac{a}{b-x}\right)
and
\tan N= \frac{c}{x} \\ \\ N=\tan^{-1}\left(\frac{c}{x}\right)

Angle θ is given by
\theta=180-M-N \\  \\ =180-\tan^{-1}\left(\frac{a}{b-x}\right)-\tan^{-1}\left(\frac{c}{x}\right)

Given that a = 4 units, b = 5 units, and c = 9 units, thus
\theta=180-\tan^{-1}\left(\frac{4}{5-x}\right)-\tan^{-1}\left(\frac{9}{x}\right)

To maximixe angle θ, the differentiation of <span>θ with respect to x must be equal to zero.
i.e.
\frac{d\theta}{dx} = -\frac{4}{x^2-10x+41} + \frac{9}{x^2+81} =0 \\  \\ -4(x^2+81)+9(x^2-10x+41)=0 \\  \\ -4x^2-324+9x^2-90x+369=0 \\  \\ 5x^2-90x+45=0 \\  \\ x^2-18x+9=0 \\  \\ x=9\pm6 \sqrt{2}

Given that x is a point on line segment AB, this means that x is a positive number less than 5.

Thus
x=9-6 \sqrt{2}=0.5147

Therefore, The distance from A of point P, so that </span>angle θ is maximum is 0.51 to two decimal places.
6 0
3 years ago
Can someone help me with this question
krek1111 [17]

Answer:

the answer would be A

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
3.90 is equivalent to how many tenths?
dlinn [17]

Answer: 39 tenths

Divide 39÷10 and get 3.9

4 0
3 years ago
What would be the equation?
laila [671]

Answer:

y= - 1/2(2)^(x)-2

Step-by-step explanation:

you could check on a graphing calculator

5 0
3 years ago
Find six rational numbers between -2 and 5
satela [25.4K]

Answer:

1/4, 0.5, -4/6, 4.5, 1/3, 7/8

explanation: it is the ratio of two integers

a/b where b is not = to 0

5 0
2 years ago
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