What type of transformation maps triangle QRS to triangle Q'R'S why?
1 answer:
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Answer:
A) 0.99413
B) 0.00022
Step-by-step explanation:
A) First of all let's find the total grading time from 6:50 P.M to 11:00 P.M.:
Total grading time; X = 11:00 - 6:50 = 4hours 10minutes = 250 minutes
Now since we are given an expected value of 5 minutes, the mean grading time for the whole population would be:
μ = n*μ_s ample = 42 × 5 = 210 minutes
While the standard deviation for the population would be:
σ = √nσ_sample = √(42 × 6) = 15.8745 minutes
To find the z-score, we will use the formula;
z = (x - μ)/σ
Thus;
z = (250 - 210)/15.8745
z = 2.52
From the z-distribution table attached, we have;
P(Z < 2.52) ≈ 0.99413
B) solving this is almost the same as in A above, the only difference is an additional 10 minutes to the time.
Thus, total time is now 250 + 10 = 260 minutes
Similar to the z-formula in A above, we have;
z = (260 - 210)/15.8745
z = 3.15
P(Z > 3.15) = 0.00022
Image is missing, so i have attached it
Answer:
21.07 mm²
Step-by-step explanation:
We will use the Formulas:
Area of semicircle = πr²/2
Area_rectangle = Length x width = Lw
We are given:
Length of rectangle = 14 mm
From the attached image, the diameter of the semicircle is equal to the length of the rectangle.
Thus;
diameter of semicircle = length of rectangle
Therefore,
diameter of semicircle = 14 mm
Also, from the attached image, the radius of the semicircle is equal to the width of the rectangle.
Thus;
diameter of semicircle/2 = radius of semicircle
Hence;
radius of semicircle = 14/2 = 7mm = width of rectangle
Thus;
Area of rectangle = L*w = 14 × 7 = 98 mm²
Area of semicircle = πr²/2 = π×7²/2 = 76.93 mm²
To get the area of the shaded region, we will subtract area of the semi-circle from the area of the rectangle.
Area of shaded region = Area_rectangle - Area_semicircle = 98 - 76.93 = 21.07 mm²
