Question

Let f(x) = cos(x). Find the x-intercepts of f(x) on [0, 2π).

Answer 1

the x-intercepts of cosx are

$\frac{\pi }{2}$ and $\frac{3\pi }{2}$ on [0, 2π )

Answer 2

Answer:

Tthe x-intercepts of f(x)= cosx on [0, 2π ) are:

$\frac{\pi }{2}$ and $\frac{3\pi }{2}$

Step-by-step explanation:

x-intercept are those values of x for which f(x)=0

So, x-intercept of  f(x)=cosx will be those values of x for which

cosx=0

cosx=0 for  

$\frac{\pi }{2}$ and $\frac{3\pi }{2}$ on [0, 2π )

Hence, the x-intercepts of f(x)= cosx on [0, 2π ) are:

$\frac{\pi }{2}$ and $\frac{3\pi }{2}$