The value of x such that f(x) = g(x) is x = 3
<h3>Quadratic equation</h3>
Given the following expressions as shown
f(x) = x^3-3x^2+2 and;
g(x) = x^2 -6x+11
Equate the expressions
x^3-3x^2+2 = x^2 -6x+11
Equate to zero
x^3-3x^2-x^2+2-11 = 0
x^3-3x^2-x^2 + 6x - 9 = 0
x^3-4x^2+6x-9 = 0
Factorize
On factorizing the value of x = 3
Hence the value of x such that f(x) = g(x) is x = 3
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Answer:
(x,y) = (-36,6)
Step-by-step explanation:
-6y=x
x+y=-30
x=-6y,
so -6y+y=-30
-5y=-30
y=6
x=-36
Hope this helps pls hit the crown :D
Answer:
Total cost = <em>$</em> 4.55
Step-by-step explanation:
2(8a + 5b) -(2a + 3b)
<em>Part A: Simplify the expression shown above</em>
Exapanding the brackets;
16a + 10b - 2a - 3b
Collecting like terms;
16a - 2a + 10b - 3b
14a + 7b
<em>Part B: If a represents apples that cost $0.25 each and b represents bananas that cost SO. 15 each, what is the total cost based on the expression above?</em>
a = 0.25
b = 0.15
14a + 7b
Inserting the values into the equation;
14 (0.25) + 7(0.15)
Total cost = <em>$</em> 4.55
Answer:
3, 4
Step-by-step explanation:
6 < 3n < 15
Divide the three "sides" by 3.
2 < n < 5
n must be between 2 and 5,a nd it must be a whole number.
n can be 3 or 4
Answer:
10y=27+7
10y=34
y=34/10
y=3.4
Step-by-step explanation:
Firstly 7 is added to 27
Then adding 7 and 27
Dividing 34 by 10
