Solve the following system of equation using any method.

Mathematics

2 answers:

tatiyna3 years ago

3 0

Answer:

X=0

Y=4

Step-by-step explanation:

3x=12-3y

x=4-y

Plug 4-y in for x in the other equation:

2(4-y)+4y=16

8-2y+4y=16

2y=8

y=4

If x=4-y and y=4, x=4-4=0

Marianna [84]3 years ago

3 0

Answer:

if y is 4 then put value of y in equation you will get x as 0

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Step-by-step explanation:

So first, let's get rid of the parentheses. We can multiply it out to get $\sqrt{16}-x\sqrt{8} =11$ . We know that the square root of 16 is ±4, so now our equation is ±4 - $x\sqrt{8}$ =11. I'm guessing since the problem only has one solution it's most likely only positive 4, so let's revise our equation to 4 - $x\sqrt{8}$ =11. We can use inverse operations to make the a little easier to solve: -7= $x\sqrt{8}$ . We divide both sides by $\sqrt{8}$ to get $\frac{-7}{\sqrt{8} } =x$ , which we can rationalize (remove the square root from the denominator so that it's a proper answer) by multiplying by $\frac{\sqrt{8} }{\sqrt{8} }$ (which is equal to one so we can use it) which is equal to $\frac{-7\sqrt{8} }{8}$ . Let's finish this by simplifying it. $\sqrt{8} =2\sqrt{2}$ (2x $2^{2}$ ). We can simplify it further by simplifying the 2, making it $\frac{-7\sqrt{2} }{4}$ .