(5x²—4x—3)+(—2x²+7x+10)

Mathematics

2 answers:

natka813 [3]3 years ago

6 0

Answer:

I am doing the question in the comments right now!!

Step-by-step explanation:

Bc i am doing something else

pav-90 [236]3 years ago

4 0

Answer 3x^2 + 3x + 7

3x^2 means 3x squared
HOPE THIS HELPS!!!

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Just help me out with this polynomial i need help <br> { -m^{2} + 6} + { -4m^{2} + 7m + 2} =

PolarNik [594]

Answer:

$-5m^2+7m+8$

Step-by-step explanation:

Here, we add up two polynomials shown.

The polynomials are:

$[-m^2 + 6]+[-4m^2 +7m + 2]$

In order to add up the 2 polynomials shown, we have to see the "like terms" and add them up.

We add up the " $m^2$ " terms and the constant (number) terms. There is one term with "m", so we leave it like that. Let's add up. Shown below:\

$[-m^2 + 6]+[-4m^2 +7m + 2]\\=-m^2-4m^2+6+2+7m\\=-5m^2+7m+8$

This is the sum of the 2 polynomials shown: $-5m^2+7m+8$

7 0

3 years ago

I need help on this hhhhhhhh

Anon25 [30]

$\huge\text{Hey there!}$

$\mathsf{\dfrac{10^{15}}{10^4}}$

$\mathsf{10^{15}}\\\mathsf{=10\times10\times10\times10\times10\times10\times10\times10\times10\times10\times 10\times10\times10\times10\times10}\\\mathsf{= \boxed{\bf 1,000,000,000,000,000}}$

$\mathsf{\dfrac{\bold{1,000,000,000,000,000}}{10^4}}$

$\mathsf{10^4}\\\mathsf{= 10\times10\times10\times10}\\\mathsf{10\times10=\bf 100}\\\mathsf{100\times100}\\\mathsf{= \boxed{\bf 10,000}}$

$\mathsf{\dfrac{1,000,000,000,000,000}{\bf 10,000}}$

$\mathsf{\dfrac{1,000,000,000,000,000}{10,000}}\\\\\mathsf{= 1,000,000,000,000,000\div 10,000}\\\\\mathsf{= \boxed{\bf 100,000,000,000}}$

$\mathsf{10^{11}}\\\mathsf{10\times10\times10\times10\times10\times10\times10\times10\times10\times10\times10}\\\mathsf{= \boxed{\bf 100,000,000,000}}$

$\mathsf{100,000,000,000= 100,000,000,000= 10^{11}}$

$\boxed{\boxed{\large\text{Answer: BASICALLY }\mathsf{\dfrac{10^1^5}{10^4}\large\text{ is EQUAL to or EQUIVALENT to}}}}\\\boxed{\boxed{\mathsf{10^{11}}\large\text{ because they both give you the result of \bf 100,000,000,000}}}\huge\checkmark$