This question too please
2 answers:
Answer: 1 year
Step-by-step explanation:
1. Make an equation for both Types in standard y = mx + b form, with “b” being how tall the tree already is (so b for Type A will be 9, and b for Type B will be 2). Let “m” be equal to how many inches each tree grows per year (m for Type A will be 17, m for Type B will be 24)
2. Now you have the equations!
Type A: y = 17x+9
Type B: y = 24x+2
3. The problem is asking for how many years (represented by “x”) it will take for the trees to be of equal height, so set both of the equations equal to each other
17x+9 = 24x+2
4. Solve! (picture attached)
I hope this helped! feel free to comment if you need any clarification, though!
Step-by-step explanation:
1. Make an equation for both Types in standard y = mx + b form, with “b” being how tall the tree already is (so b for Type A will be 9, and b for Type B will be 2). Let “m” be equal to how many inches each tree grows per year (m for Type A will be 17, m for Type B will be 24)
2. Now you have the equations!
Type A: y = 17x+9
Type B: y = 24x+2
3. The problem is asking for how many years (represented by “x”) it will take for the trees to be of equal height, so set both of the equations equal to each other
17x+9 = 24x+2
4. Solve! (picture attached)
I hope this helped! feel free to comment if you need any clarification, though!
You might be interested in
Answer:
12.7m
Step-by-step explanation:
The equation for motion to be used to find how far the water travels is
xf = xi + Vix(t) + 1/2axt^2
xf = 0 + ViCos α(t) + 0
xf = ViCosα(t)
xf = 12 Cos 30°(t)
xf = (6√3)t
To find the total times we will use the vertical displacement equation
yf = yi + Viy(t) + 1/2ayt^2
0 = 0 + ViSinα(t) + (1/2 * (-9.8)t^2)
0 = 12Sin30°(t) - 4.9t^2
4.9t^2 = 12Sin30°(t)
4.9t^2 = 6t
Divide through by t
4.9t = 6
t = 6/4.9
t = 1.22secs
Put t = 1.22 into (6√3)t
xf = 6√3 * 1.22
xf = 12.7m
