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Reika [66]
3 years ago
14

Answer to get 20 points and brainleiest

Mathematics
2 answers:
ddd [48]3 years ago
8 0

Answer:

x=10/7

Step-by-step explanation:

dalvyx [7]3 years ago
7 0

Answer:

last anwer beacuse it 10 divided by 7 equal 10/7

Step-by-step explanation:

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Help please!!
Luden [163]

Answer:

7.5 km ggggggggggg ghhk

5 0
3 years ago
I need help ! asap !
kotegsom [21]

Answer:

52

Step-by-step explanation:

A(2) + B(2) = C(2)

10(2) + 24(2)

     676    = C(2)

  square root of 676

           AC=26      BD=26

AC + BD

26 + 26 =

     52

Hope this helps

6 0
3 years ago
A data set includes the following grades: 98, 94, 93, 82, 61, 80. Suppose that 61 is removed from the data. How is the median af
andre [41]

Answer:b

Step-by-step explanation:

A data with values

98,94,93,82,61,80 is given

If we arrange the number according to their values

61,80,82,93,94,98

Median of set

\frac{82+93}{2}=87.5

Now if 61 is removed then

80,82,93,94,98 are the remaining data

so New median is 93

So the median is increased by 5.5

Therefore option b is correct

5 0
4 years ago
Which expression is equivalent to 2(x-3) + 4
GenaCL600 [577]

Answer:

2x - 2

Step-by-step explanation:

Order of Operations: BPEMDAS

Step 1: Distribute parenthesis

2x - 6 + 4

Step 2: Combine like terms

2x - 2

And we have our answer!

6 0
3 years ago
Read 2 more answers
A trucks relation to a car is -60. The car and truck move in the same direction. The car moves five times as fast for 8 seconds.
tino4ka555 [31]

Explanation:

We are not given units for distance or speed. The only units we're given are for time (seconds). Let the car's speed be represented by "v".

When the truck is moving 5 times as fast as the car, its relative speed is ...

  5v -v = 4v

For some time (t) at the higher speed, it will move a distance farther than the car moves. That distance is the product of the relative speed and the corresponding time period: 4vt. Since the speeds are in the same direction, this additional distance is added to the initial relative location of the truck, -60. The new position of the truck relative to the car is ...

  -60 +4vt = -60 +4v(8 seconds)

  -60 + 32v . . . . . new position of the truck in relation to the car

(This only makes sense if the units of v are the same distance units as -60 and time units of seconds.)

__

At least, operations of multiplication and addition are needed. Depending on the units of speed and distance, units conversion may also be required.

5 0
3 years ago
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