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nlexa [21]
3 years ago
15

Find the equation of the quadratic function with zeros 10 and 14 and vertex at (12, -8).

Mathematics
1 answer:
Eduardwww [97]3 years ago
4 0
We'll do the same we did on the previous one, using the vertex form.

our vertex is at (12, -8) thus h = 12, k = -8

and our zeros are 10, 0 and 14,0, so.. .we'll use say  hmm (10,0) to get the "a" coefficient.

\bf \qquad \textit{parabola vertex form}\\\\
\begin{array}{llll}
\boxed{y=a(x-{{ h}})^2+{{ k}}}\\\\
x=a(y-{{ k}})^2+{{ h}}
\end{array} \qquad\qquad  vertex\ ({{ h}},{{ k}})\\\\
-------------------------------\\\\
vertex\ (12,-8)\  
\begin{cases}
h=12\\
k=-8
\end{cases}\implies y=a(x-12)^2-8
\\\\\\
\textit{we also know that }
\begin{cases}
y=0\\
x=10
\end{cases}\implies 0=a(10-12)^2-8
\\\\\\
8=a(-2)^2\implies 8=4a\implies \boxed{2=a}
\\\\\\
thus\qquad \boxed{y=2(x-12)^2-8}
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