Ask question

Ask question

All categories

3 years ago

10

What are exponent rules?

1 answer:

creativ13 [48]3 years ago

4 0

Below is List of Rules<span> for </span>Exponents<span> and an example or two of using each </span>rule: Zero-Exponent Rule: a0<span> = 1, this says that anything raised to the zero power is 1. Power</span>Rule<span> (Powers to Powers): (a^</span>m)^n<span> = a^</span>mn<span>, this says that to raise a power to a power you need to multiply the </span>exponents<span>.</span>

You might be interested in

Which list is in order from least to greatest?

Alex Ar [27]

|-9|, |-3.5|, |4.2| is the answer. row 3

7 0

3 years ago

√(2x+1)<br> Evaluate the integral<br> 2<br> (2x + 1) In (2x + 1)<br> dx.

Crank

Substitute $y=\ln(2x+1)$ and $dy=\frac2{2x+1}\,dx$ , so that

$\displaystyle \int \frac2{(2x+1) \ln(2x+1)} \, dx = \int \frac{dy}y = \ln|y| + C = \boxed{\ln|\ln(2x+1)| + C}$

6 0

1 year ago

Corey spent 18 minutes coloring. She spent 6 times as many minutes reading

ruslelena [56]

Answer:

18 x 6 =108. she spent 108 minutes reading.

Step-by-step explanation:

3 0

2 years ago

Round 0.581 to the nearest tenth.

Furkat [3]

The answer is 0.6, 5 or higher add one more, 4 or less stays the same

5 0

3 years ago

The class average on a math test was an 82 with a standard deviation of 5. If the

Alex787 [66]

Answer:

Option 3 and 4.

Step-by-step explanation:

The z score shows by how many standard deviations the raw score is above or below the mean. The z score is given by:

$z=\frac{x-\mu}{\sigma} \\\\where\ x=raw\ score,\mu=mean, \ \sigma=standard\ deviation$

Given that mean (μ) = 82, standard deviation (σ) = 5

1) For x = 74:

$z=\frac{x-\mu}{\sigma} \\\\z=\frac{74-82}{5} =-1.6$

Option 1 is incorrect

2) For x < 87

$z=\frac{x-\mu}{\sigma} \\\\z=\frac{87-82}{5} =1$

From the normal distribution table, P(x < 87) = P(z < 1) = 0.8413 = 84.13%

Option 2 is incorrect

3) For x = 95:

$z=\frac{x-\mu}{\sigma} \\\\z=\frac{95-82}{5} =2.6$

Option 3 is correct

4) For x < 77

$z=\frac{x-\mu}{\sigma} \\\\z=\frac{77-82}{5} =-1$

From the normal distribution table, P(x < 77) = P(z < -1) = 0.16 = 16%

Option 4 is correct

5) For x > 92

$z=\frac{x-\mu}{\sigma} \\\\z=\frac{92-82}{5} =2$

From the normal distribution table, P(x > 92) = P(z > 2) = 1 - P(z < -2) = 1 - 0.9772 = 0.0228 = 2.28%

Option 5 is incorrect

8 0

3 years ago