On a piece of paper, use a protractor to construct a triangle with angle measures of 30° and 50º.

Suppose twenty-two communities have an average of = 123.6 reported cases of larceny per year. assume that σ is known to be 36.8

Delvig [45]

We are given the following data:

Average = m = 123.6
Population standard deviation = σ= psd = 36.8
Sample Size = n = 22

We are to find the confidence intervals for 90%, 95% and 98% confidence level.

Since the population standard deviation is known, and sample size is not too small, we can use standard normal distribution to find the confidence intervals.

Part 1) 90% Confidence Interval
z value for 90% confidence interval = 1.645

Lower end of confidence interval = $m-z *\frac{psd}{ \sqrt{n} }$
Using the values, we get:
Lower end of confidence interval= $123.6-1.645* \frac{36.8}{ \sqrt{22}}=110.69$

Upper end of confidence interval = $m+z *\frac{psd}{ \sqrt{n} }$
Using the values, we get:
Upper end of confidence interval= $123.6+1.645* \frac{36.8}{ \sqrt{22}}=136.51$

Thus the 90% confidence interval will be (110.69, 136.51)

Part 2) 95% Confidence Interval
z value for 95% confidence interval = 1.96

Lower end of confidence interval = $m-z *\frac{psd}{ \sqrt{n} }$
Using the values, we get:
Lower end of confidence interval= $123.6-1.96* \frac{36.8}{ \sqrt{22}}=108.22$

Upper end of confidence interval = $m+z *\frac{psd}{ \sqrt{n} }$
Using the values, we get:
Upper end of confidence interval= $123.6+1.96* \frac{36.8}{ \sqrt{22}}=138.98$

Thus the 95% confidence interval will be (108.22, 138.98)

Part 3) 98% Confidence Interval
z value for 98% confidence interval = 2.327

Lower end of confidence interval = $m-z *\frac{psd}{ \sqrt{n} }$
Using the values, we get:
Lower end of confidence interval= $123.6-2.327* \frac{36.8}{ \sqrt{22}}=105.34$
Upper end of confidence interval = $m+z *\frac{psd}{ \sqrt{n} }$
Using the values, we get:
Upper end of confidence interval= $123.6+2.327* \frac{36.8}{ \sqrt{22}}=141.86$

Thus the 98% confidence interval will be (105.34, 141.86)

Part 4) Comparison of Confidence Intervals
The 90% confidence interval is: (110.69, 136.51)
The 95% confidence interval is: (108.22, 138.98)
The 98% confidence interval is: (105.34, 141.86)

As the level of confidence is increasing, the width of confidence interval is also increasing. So we can conclude that increasing the confidence level increases the width of confidence intervals.

3 0

3 years ago

Determine if the following triangles are congruent by SSS or SAS.

Sergeu [11.5K]

Answer:

They are congruent by SAS (Side Angle SIde) test or congruence criterion

Since,

In triangle ABD and triangle BCD

AB = BC (Given)

BD = DB(Common Side)

Angle ABD = Angle CBD

Therefore triangle ABD and triangle BCD by SAS (Side Angle SIde) test or congruence criterion

6 0

2 years ago

Calculate 6 P 6 note n p r equals n Over N - r

Murrr4er [49]

Answer:

7

Step-by-step explanation:

n! Might be 7, and n might be 6. r might also be 6. So 6 - 6= 0! = 1

So I think it might be 7 ÷ 1, which is 7.

7 0

3 years ago

A recipe uses 5 cups of water for<br> every 3 cups of flour?

Lerok [7]

Answer:

There's no context for a conclusion.

Step-by-step explanation:

Comment when you've edited the question.

6 0

2 years ago

Hi what is 2/5 times 6/8

guajiro [1.7K]

Answer:

12/40 (simplified = 3/10)

Step-by-step explanation:

2 x 6 = 12

5 x 8 = 40

5 0

2 years ago

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