Answer:
0 < r < r_exterior B_total = 
r > r_exterior B_total = 0
Explanation:
The magnetic field created by the wire can be found using Ampere's law
∫ B. ds = μ₀ I
bold indicates vectors and the current is inside the selected path
outside the inner cable
B₁ (2π r) = μ₀ I
B₁ =
the direction of this field is found by placing the thumb in the direction of the current and the other fingers closed the direction of the magnetic field which is circular in this case.
For the outer shell
for the case r> r_exterior
B₂ = \frac{\mu_o I}{2\pi r}
This current is in the opposite direction to the current in wire 1, so the magnetic field has a rotation in the opposite direction
for the case r <r_exterior
in this case all the current is outside the point of interest, consequently not as there is no internal current, the field produced is zero
B₂ = 0
Now we can find the field created by each part
0 < r < r_exterior
B_total = B₁
B_total =
r > r_exterior
B_total = B₁ -B₂
B_total = 0
In optics, you have to create a layer of coating that is approximately 1/4 of the light's wavelength. The working equation for this problem is:
d = λ₀/4n,
where
λ₀ is the wavelength of the incident light
n is the refractive index of the coating
Substituting the values,
d = (650 nm)/4(1.39)
<em>d = 116.9 nm</em>
Answer:
Clockwise and counter clockwises, depands.
Explanation:
The direction of current in a loop of wire in a magnatic field depands on the direction in which the loop is moved and the applied magnatic field.
this is determined by what is called right hand rule.
I will give one scenario, let's say that the loop is moved upwards and the applied magnatic field is into the page (if you drew the loop in 2D on a piece of paper), in this case the direction would be clockwise.
Answer:
2) f = 0.707 Hz
Explanation:
Given m₁ = 1.0 kg , f₁ = 1.0 Hz
So using the equation
f₁ = ( 1 / 2 π ) * √K / m₁
Solve to determine K' constant of spring
K = m * ( 4 π ² * f ² )
K = 1.0 kg * ( 4 π ² 1.0² Hz )
K = 39.4784176
So given 2.0 kg the frequency can be find using formula
f₂ = ( 1 / 2 π ) * √K / m₂
f₂ = ( 1 / 2 π ) * √39.4784176 / 2.0 kg
f₂ = 0.707 Hz
Answer:
250N
Explanation:
weight = Mass(in kg) × Gravitational field strength
25 × 10 = 250N
