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coldgirl [10]
3 years ago
7

A shopping cart is pushed with 35 N of force to the right. It moved to the right 4m. What was the work done to the grocery cart.

Physics
1 answer:
Ratling [72]3 years ago
4 0

Answer:

140 N-m

Explanation:

Work done is equal to the product of force and displacement  

Here in this case,  

Force = weight of the cart

Displacement = distance moved by the cart

Work done = Force x displacement

= 35 N x 4 m

= 140 N-m

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a car accelerates from rest at 3 m / s^2 along a straight road. how far has the car travelled after 4 s
evablogger [386]

Answer:

24 m

Explanation:

The motion of the car is a uniformly accelerated motion (=at constant acceleration), therefore we  can find the distance covered by using the following suvat equation:

s=ut+\frac{1}{2}at^2

where

s is the distance covered

u is the initial velocity

t is the time elapsed

a is the acceleration

For the car in this problem:

u = 0, since the car starts from rest

a=3 m/s^2 is the acceleration

t = 4 s is the time elapsed

Therefore, the distance covered is:

s=0+\frac{1}{2}(3)(4)^2=24 m

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Explanation:

Given that,

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According to Hooke's law, the force exerted by the spring is given by :

F = kx

k is the spring constant

k=\dfrac{F}{x}

k=\dfrac{600\ N}{0.04\ m}

k = 15000 N/m

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