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Archy [21]
4 years ago
5

Two vectors and have the components, in meters, ax = 6.91, ay = 1.45, bx = 2.45, by = 7.02. (a) find the angle between the direc

tions of and . there are two vectors in the xy plane that are perpendicular to and have a magnitude of 8.28 m. one, vector , has a positive x component and the other, vector , a negative x component. what are (b) the x component and (c) the y component of , and (d) the x component and (e) the y component of vector ?
Mathematics
1 answer:
White raven [17]4 years ago
8 0
We are given
ax = 6.91
ay = 1.45

bx = 2.45
by = 7.02

So,
tan a→ = 1.45/6.91 = 0.2098 = ma
tan b→ = 7.02/2.45 = 2.8653 = mb

To get the angle between the two
tan θ = (mb - ma)/(1 + ma mb)
tan θ = (2.8653 - 0.2098) / (1 + (2.8653) (0.2098) )
θ = 58.91°
The x component is
x = 8.28 cos 58.91 = 4.28 m
The y component is
y = 8.28 sin 58.91 =  7.09 m
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An elevator can hold a maximum of 1500 pounds. An average child weighs 75 pounds and the average adult weighs 150 pounds. The el
CaHeK987 [17]

<u>Let's take this problem step-by-step</u>:

<u>Let's first set up some variables</u>:

  • c: # of children
  • a: # of adults

<u>Let's examine the information given:</u>

  • Elevator can hold a maximum of 1500 pounds

          ⇒ average child is 75 pounds

          ⇒ average adult is 150 pounds

                 ⇒<em> therefore</em>: 75c + 150a\leq 1500

  • Elevator can fit no more than 14 people

          ⇒ <em>therefore</em>: c + a \leq 14

<u>Let's graph the equations</u>:

 75c+150a\leq 1500\\c+a\leq 14

    ⇒ look at the image attached

<u>The point at which the two graphs intersect:</u>

  ⇒ <em>is the solution that represents the amount of children and adults and </em>

<em>       their combine weight</em>

<em />

<u><em>With the horizontal axis being the # of children and vertical axis being the # of adults</em></u><em>:</em>

<em>  ⇒ the </em><em>solution is 8 children and 6 adults</em>

<em></em>

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7 0
2 years ago
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Answer:

f(-2) = 0

f(1) = 12

f(2) = 5

Step-by-step explanation:

f(-2) will lie in the function f(x) =x^2 - 4

\therefore f( - 2) =  {( - 2)}^{2}  - 4 = 4 - 4 = 0

f(1) will lie in the function f(x) =2x^2 +10

\therefore f(1) = 2 {(1)}^{2}  + 10 = 2 + 10 = 12

f(2) will lie in the function f(x) =5

\therefore f(2) = 5

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6 0
4 years ago
Read 2 more answers
Topic: The Quadratic Formula
Finger [1]

Answer:

Step-by-step explanation:

The quadratic formula for a equation of form

ax²+bx + c = 0 is

x= \frac{-b +- \sqrt{b^2-4ac} }{2a}

For the first equation,

x²+3x-4=0,

we can match that up with the form

ax²+bx + c = 0

to get that

ax² =  x²

divide both sides by x²

a=1

3x = bx

divide both sides by x

3 = b

-4 = c

. We can match this up because no constant multiplied by x could equal x² and no constant multiplied by another constant could equal x, so corresponding terms must match up.

Plugging our values into the equation, we get

x= \frac{-3 +- \sqrt{3^2-4(1)(-4)} }{2(1)} \\= \frac{-3+-\sqrt{25} }{2} \\ = \frac{-3+-5}{2} \\= -8/2 or 2/2\\=  -4 or 1

as our possible solutions

Plugging our values back into the equation, x²+3x-4=0, we see that both f(-4) and f(1) are equal to 0. Therefore, this has 2 real solutions.

Next, we have

x²+3x+4=0

Matching coefficients up, we can see that a = 1, b=3, and c=4. The quadratic equation is thus

x= \frac{-3 +- \sqrt{3^2-4(1)(4)} }{2(1)}\\= \frac{-3 +- \sqrt{9-16} }{2}\\= \frac{-3 +- \sqrt{-7} }{2}\\

Because √-7 is not a real number, this has no real solutions. However,

(-3 + √-7)/2 and (-3 - √-7)/2 are both possible complex solutions, so this has two complex solutions

Finally, for

4x² + 1= 4x,

we can start by subtracting 4x from both sides to maintain the desired form, resulting in

4x²-4x+1=0

Then, a=4, b=-4, and c=1, making our equation

x=\frac{-(-4) +- \sqrt{(-4)^2-4(4)(1)} }{2(4)} \\= \frac{4+-\sqrt{16-16} }{8} \\= \frac{4+-0}{8} \\= 1/2

Plugging 1/2 into 4x²+1=4x, this works as the only solution. This equation has one real solution

7 0
3 years ago
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