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3 years ago

Trig questions above solve for x and round to the nearest tenth

Mathematics

1 answer:

Alik [6]3 years ago

7 0

Answer:

x= 51.3

x=35.1

Step-by-step explanation:

10.)

For this one we have the adjacent side and the hypotonouse

Which means we'll use CAH

cos(x)=25/40

x= 51.31781255

(assuming that we have to round to the nearest tenth again)

x=51.3

12.)

For this one we have the adjacent and hyptonouse

we'll use CAH again

cos(x)=27/33

x= 35.09680123

x=35.1

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Let f(x) = x - 3 and g(x) = x + 11 find f(x) times g(x)<br><br> What is the answer?

notsponge [240]

f(x) *g(x) = (x-3)(x+11) = x^2 +11x -3x -33 = x^2 +8x -33

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3 years ago

The length of a parasite in experiment A is 2.5 × 10–3 inch. The length of a parasite in experiment B is 1.25 × 10–4 inch. How m

torisob [31]

We have been given that :-

The length of a parasite in experiment A is $2.5 \times 10^{-3}$

The length of a parasite in experiment B is $1.25 \times 10^{-4}$

Let us write the the length of the parasite in experiment A in the exponent of -3.

$1.25 \times 10^{-4}= 0.125 \times 10^{-3}$

Clearly, the length of parasite in experiment A is greater than the length of parasite in experiment B.

The difference in the length is given by

$2.5 \times 10^{-3} -0.125 \times 10^{-4}$

$=2.375 \times 10^{-3}$

Therefore, the length of the parasite in experiment A is $=2.375 \times 10^{-3}$ inches greater than the length of the parasite in experiment B.

3 0

3 years ago

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What number would represent 6.9 meters below sea level? *

rewona [7]

Answer:

Step-by-step explanation:

Its actually -6.9

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3 years ago

A circle has a radius of 4 ft. What is the area of the sector formed by a central angle measuring 3π2 radians? Use 3.14 for pi.

Vikki [24]

Answer:

The answer is 37.68 I just took the test.

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3 years ago

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An open box is to be made out of a 12-inch by 20-inch piece of cardboard by cutting out squares of equal size from the four corn

Natali5045456 [20]

Answer:

Length = 15.14, width = 7.14 and height = 2.43 inches.

( correct to the nearest hundredth).

Step-by-step explanation:

Let the lengths of the squares cut out be x inches.

Then the width of the box will be 12 - 2x and the length will be

20 - 2x inches.

The height of the box is x inches.

Volume V = x(20-2x)(12-2x)

To find the value of x when V is a maximum we find the derivative and equate it to zero.

V = x( 240 - 64x + 4x^2)

V = 4x^3 - 64x^2 + 240x

dV/dx = 12x^2 - 128x + 240 = 0

4(3x^2 - 32x + 60) = 0

This won't factor so we use the formula:

x = [-(-32) +/- √((-32)^2 - 4*3*60)] / 6

= 8.24, 2.43.

So one of these gives a maximum Volume.

The second derivative

d^2V/dx^2 = 24x - 128

When x = 8.24, this = 69.6 (positive) so this gives a minimum.

x = 2.43 gives a negative value ( -49.7) so this is the maximum

So the dimensions are:-

length = 20 - 2(2.43) = 15.14

width = 12 - 2(2.43) = 7.14

height = 2.43.

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2 years ago