3 years ago

Two offices are participating in a weight loss challenge.

Mathematics

1 answer:

Lynna [10]3 years ago

4 0

Answer: Cannot answer

Step-by-step explanation: What is your question?

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Find the zeroes of the following equation:

weqwewe [10]

Answer: $\bold{x=\dfrac{1\pm \sqrt5}{2}}$

both zeros are irrational numbers

<u>Step-by-step explanation:</u>

Note: The question would have made more sense if if it was 2/x = x - 1 but I will answer it as written.

$\dfrac{1}{x}=x-1\qquad \text{Restriction: }x\neq 0\\\\\\\text{Cross multiply, simplify, and set equal to zero:}\\1=x(x-1)\\\\1=x^2-x\\\\0=x^2-x-1\\\\\\\text{This is not factorable so you will need to use Quadratic Formula:}\\\\x=\dfrac{-(-1)\pm \sqrt{(-1)^2-4(1)(-1)}}{2(1)}\\\\\\x=\dfrac{1\pm \sqrt5}{2}$