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Andrews [41]
3 years ago
15

How would the table change if the pattern was multiply the number of tanks by 8

Mathematics
1 answer:
Levart [38]3 years ago
8 0
How would the table change if the pattern was multiply the number of tanks by 8
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A parallelogram has coordinates A(1, 1), B(5, 4), C(7, 1), and D(3, -2). What are the coordinates of parallelogram A′B′C′D′ afte
saul85 [17]

Hey there! I'm happy to help!

First, we need to rotate our points 180° about the origin. To find the coordinates after such a rotation, we simply find the negative version of each number in the ordered pair, which can be written as (x,y)⇒(-x,-y).

Let's convert this below

A: (1,1)⇒(-1,-1)

B: (5,4)⇒(-5,-4)

C: (7,1)⇒(-7,-1)

D: (3,-2)⇒(-3,2)

Now, we need to translate these new points five units to the right and one unit down. This means we will add 5 to our x-value and subtract 1 from our y-value. This will look like (x,y)⇒(x+5,y-1). Let's do this below.

A: (-1,-1)⇒(4,-2)

B: (-5,-4)⇒(0,-5)

C: (-7,-1)⇒(-2,-2)

D: (-3,2)⇒(2,1)

Therefore, this new parallelogram has coordinates of A'(4,-2), B'(0,-5), C'(-2,-2), and D'(2,1)

Now you know how to find the coordinates of translated figures! Have a wonderful day! :D

5 0
3 years ago
Factor completely. x^3 + 2x^2 + x + 2
slega [8]
x^3 + 2x^2 + x + 2=\\
x^2(x+2)+1(x+2)=\\
(x^2+1)(x+2)
8 0
3 years ago
PLEASE HELP<br> I WILL MARK BRAINIEST
leonid [27]

Answer:

1: Rhombus

2: Square

3: Rectangle

4: Trapezoid (isosceles trapezoid to be exact)

4 0
3 years ago
Read 2 more answers
Evaluate 6 C 3 .<br><br> 18<br> 20<br> 60<br> 120
Novosadov [1.4K]
The answer will be 6 x 5 x 4 / 3 x 2 x 1,    5 x 4 = 20. Hope this helps
5 0
3 years ago
I just need answers to the odd numbered questions.<br> I would appreciate the help<br><br> 35 points
Misha Larkins [42]

Answer:

Step-by-step explanation:

Combine real terms and combine complex terms

1) 3 + 2i + 2 - 5i = 3 +2 + 2i - 5i

                          = 5 + (2-5)i

                          = 5 + (-3)i

                          = 5 - 3i

3) 2 - (1 - 2i) + (4 -5i ) - (1 - 3i)  = 2 -1 + 2i + 4 - 5i - 1 + 3i

           {- is distributed to (1 - 2i) & - is distributed to (1- 3i)}

              = 2 - 1  + 4 + 1 + 2i - 5i + 3i

              = 6 +0i = 6

5) 4 - 3i + 4 + 3i = 4 +4 -3i + 3i

                          = 8

7) (3 - 2i)² + (3 +2i) = 3² - 2*3*2i + (2i)² + 3 + 2i     {(a - b)² = a² - 2ab +b²}

= 9 -12i + 4i² + 3 + 2i

= 9 - 12i + 4*(-1) + 3 + 2i       {i²  = -1}

= 9 +3 - 4 - 12i +2i

= 8 - 10i

9) (a +b)^{4} - (a - b)^{4} = 8ab(a^{2} +b^{2})\\\\\\Here, \ a = 1 \ and \ b = i\\\\\\(1+\sqrt{-1})^{4}-(1-\sqrt{-1})^{4}=(1+\sqrt{i^{2}})^{4}-(1-\sqrt{i^{2}})^{4}\\\\=(1+i)^{4}-(1-i)^{4}\\\\=8*1*i(1^{2}+i^{2})\\\\=8i*(1 -1)\\\\=8i*0\\\\=0

6 0
3 years ago
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