The recursive formula of h(n) is h(1) = 36 and h(n) = h(n -1) - 5
<h3>How to determine the recursive formula?</h3>
The function is given as:
h(n) = 41- 5n
Calculate h(1) and h(2)
h(1) = 41- 5(1)
h(1) = 36
h(2) = 41- 5(2)
h(2) = 31
Calculate the difference between h(1) and h(2)
d = 31 - 36
d = -5
This means that:
h(1) = 36 and h(n) = h(n -1) - 5
Hence, the recursive formula of h(n) is h(1) = 36 and h(n) = h(n -1) - 5
Read more about recursive formula at:
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Answer:
Area of the triangle = 0
Step-by-step explanation:
We are given the vertices of a triangle as: (- 8,4 ), (- 6,6), (- 3,9)
The formula to find the Area of the triangle =
1/2[ x₁(y₂ - y₃) + x₂(y₃ - y₁) + x₃(y₁ - y₂)]
Where :
(x₁, y₁) = (- 8,4 )
(x₂, y₂) = (- 6,6)
(x₃, y₃) = (- 3,9)
Area of the triangle = 1/2[-8(6 - 9) + -6(9 - 4) + -3(4 - 6)]
= 1/2[ (-8 × -3) +( -6 × 5) +( -3× -2)]
= 1/2[ 24 - 30 + 6)
= 1/2[ 24 + 6 - 30]
= 1/2 [30 - 30]
=1/2[ 0 ]
= 0
Therefore, the area of triangle whose vertices are (- 8,4 ), (- 6,6) and (- 3,9) is ZERO( = 0 )
Answer:
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Here is the answer. Hope I got the answer right