Answer:
The minimum weight for a passenger who outweighs at least 90% of the other passengers is 203.16 pounds
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:

What is the minimum weight for a passenger who outweighs at least 90% of the other passengers?
90th percentile
The 90th percentile is X when Z has a pvalue of 0.9. So it is X when Z = 1.28. So




The minimum weight for a passenger who outweighs at least 90% of the other passengers is 203.16 pounds
Step-by-step explanation: the answer is x = 1/2
Answer:
SAS Similarity
Step-by-step explanation:
ΔOPQ similar to ΔRST
∠Q = ∠T
OQ : RT = 28 : 84 = 1 : 3
QP : TS = 16 : 48 = 1 : 3
The measures of two sides of ΔOPQ are proportional to the measure of two side of ΔRST and their included angles are congruent. The triangles are similar by SAS Similarity.
Charlie browns Christmas- 31.25%
How the grinch stole Christmas- 25%
Rudolph the red nosed reindeer- 37.5%
Frosty the snowman- 6.25%
Radius
is half of the circle
diameter
is the whole thing inside the circle
since it is a radius, and it is a half of the full circle, we need to double out that number, and multiply by 2.
so here, you said it is 28
take 28, and multiply by 2, if you do every thing correctly, you should get:
56
so then answer would be 56 centimeters.
Hope that this helps you! =)