The point (2, -5) would not be one of the correct vertices of the reflected shape.
When we reflected a shape across the line y=x, we just replace the x's with y's and y's with x's.
Our new points are (5, 2) (4, 6) and (3, 3). None of the points contain negative numbers.
28/11.2 = 2.5
since they are similar and openly stated as parrallelograms, you know that they have a scale of the longest edge of EFGH to the longest edge of JKLM
Add the 8 to 24 and divide 32 by 2
Tal vez deberia buscar las respuestas en internet
Answer:
160 pages
Step-by-step explanation:
80/100×200
=160
