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Rama09 [41]
3 years ago
8

Describe a real-world situation in which you would use a division equation to solve a problem. Write your equation and solve it.

Mathematics
1 answer:
Liono4ka [1.6K]3 years ago
6 0
Because how u worked it out is the way I do it
You might be interested in
If g(x) is the inverse of f(x) and f(x) = 4x+12, what is g(x)?
prohojiy [21]

Answer:

D

Step-by-step explanation:

y=4x+12

x=4y+12

x-12=4y

1/4x-3

4 0
3 years ago
Which of the following is the equation of a circle with a radius of 10 cm and center at (–3, 6)?
vlabodo [156]

The equation of a circle is (x - h)² + (y - k)² = radius² where (h, k) is the ordered pair for the center.

(x - (- 3))² + (y - 6)² = 10²

(x + 3)² + (y - 6) = 100

5 0
3 years ago
Out of every 40 pens, 5 pens are discarded. What percent of the pens are not discarded?
Gwar [14]

87.5 percent

Reason: 40/40-5/40 is 35/40. Divide 35/40 and you get 0.875. Multiply by a hundred and you get 87.5%

3 0
3 years ago
One angle in an obtuse isosceles triangle measures 40°. What are the measures of the other two angles?
Damm [24]
An obtuse triangle has one obtuse angle, or an angle that measures more than 90° but less than 180°. Options 1 and 2 are not correct, because these are acute angles.
So, one of the angles must be 40°, and the other may be 100° or 120°.
The measures of the angles in a triangle add up to 180°.
40^\circ + 40^\circ +x = 180^\circ \\
80^\circ + x=180^\circ \\
x=180^\circ - 80^\circ \\
x=100^\circ
The other two angles are 40° and 100°.
5 0
3 years ago
Read 2 more answers
Babcock and Marks (2010) reviewed survey data from 2003–2005 and obtained an average of μ = 14 hours per week spent studying by
Dmitry [639]

Answer:

We do not have enough evidence to accept H₀

Step-by-step explanation:

Normal Distribution

size sample  =  n = 64   (very small sample for evaluating population of 5  years

Standard deviation 4,8

1.- Test hypothesis

H₀             null hypothesis        ⇒               μ₀ = 14       and

Hₐ     alternative hypothesis   ⇒                μ₀ ≠ 14

2.- z(c)  we assume α = 0,05  as we are dealing with a two test tail we should  consider   α/2  = 0.025.

From z table we the z(c) value

z(c) = 1.96           and of course by symmetry   z(c) = -1.96

3.- We proceed to compute z(s)

z(s)  = [ (  μ -  μ₀ ) /( σ/√n) ]           ⇒    z(s)  = - (1.5)*√64/4.8

z(s)  = - 2.5

We compare z(s)  and z(c)

z(s) < z(c)     -2.5  < -1.96  meaning  z(s) is in the rejection zone

we reject H₀ .

From the start we indicate sample size as to small for the experiment nonetheless we found that we dont have enough evidence to accept H₀

6 0
3 years ago
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