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Ulleksa [173]
3 years ago
8

Which is NOT proportionate to 15/45 3/9 3/15 1/3 30/90

Mathematics
1 answer:
ivann1987 [24]3 years ago
3 0
You would reduce each of them down by dividing both the top and bottom by the same number, so 15/45 turns into 1/3
3/9 - 1/3
3/15 - 1/5
1/3
30/90 - 1/3
The only one that's different is 3/15
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9 Josie parents opened a college
mixer [17]

Answer:

$1,281.00

Step-by-step explanation:

We start by calculating the value $50 added each month after the first month

= $50 × 11

= $550

Calculation:

First, converting R percent to r a decimal

r = R/100 = 5.5%/100 = 0.055 per year.

P = Principal = 500 + 550

= $1050

Calculation:

First, converting R percent to r a decimal

r = R/100 = 5.5%/100 = 0.055 per year.

Solving our equation:

A = 1050(1 + (0.055 × 4)) = 1281

A = $1,281.00

Therefore, there would be $1,281.00 after 4 years.

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3 years ago
Which term below is a "like term" to 2xy2?<br><br> a, 3xy2<br> b, -x2y<br> c, -5<br> d, 4xy
BigorU [14]

Answer:

The answer is

A 3xy^2

Step-by-step explanation:

Im assuming that in the question it is 2xy^2 and that answer choice A is 3xy^2

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3 years ago
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The volume of prism having its base a right angled triangle is 864cm^3.if the length of the sides containing the right angle are
Scrat [10]

Answer:

height: 36 cm

Step-by-step explanation:

volume of triangle prism = 0.5 * base * altitude * height

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2 years ago
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Real Estate One conducted a recent survey of house prices for properties located on the shores of Tawas Bay. Data on 26 recent s
Ivanshal [37]

Answer:

Step-by-step explanation:

Hello!

Given the data for the variables:

Y: Selling price of a house on the shore of Tawas Bay

X₁: Number of bathrooms of a house on the shore of Tawas Bay.

X₂: Square feet of a house on the shore of Tawas Bay.

X₃: Number of bedrooms of a house on the shore of Tawas Bay.

The multiple regression model is Y= α + β₁X₁ + β₂X₂ + β₃X₃ + εi

a. Using software I've entered the raw data and estimated the regression coefficients:

^α= a= -5531.01

Represents the mean selling price of the houses when 0 bathrooms, 0 square feet and 0 bedrooms.

^β₁= b₁= -1386.21

Represents the modification of the mean selling price of the houses when the number of bathrooms increases in one unit and the square feet and number of bedrooms remain unchanged.

^β₂= b₂= 60.28

Represents the modification of the mean selling price of the houses when the square feet increase in one unit and the number of bathrooms and bedrooms remain unchanged.

^ β₃= b₃= 54797.08

Represents the modification of the mean selling price of the houses when the number of bedrooms increase in one unit and the number of bathrooms and square feet of the houses remain unchanged.

^Y= -5531.01 -1386.21X₁ + 60.28X₂ + 54797.08X₃

b)

R²= 0.55

R²Aj= 0.49

The coefficient of determination gives you an idea of how much of the variability of the dependent variable (Y) is due to the explanatory variables. Each time you add another explanatory variable to the regression the coefficient increases regarding of real contribution of the new variable. This could lead to thinking (wrongly) that the new variables are good to explain the dependent variable.  

The adjusted coefficient of determination is a correction made to the raw coefficient of determination to have a more unbiased estimation of the effect the independent variables have over the dependent variable.

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c)

The standard error estimate, this is the estimate of the population variance of the errors. In the ANOVA is represented by the Mean Square of the errors (MME)

Se²= MME= 3837640577.01

Se= 61948.6931

d) and f)

For the hypotheses tests for each slope the t- and p-values are:

α: 0.05

β₁: t_{H_0}= \frac{b_1-\beta_1 }{Sb_1} t= -0.06; p-value: 0.9528 ⇒ Do not reject H₀, the test is not significant.

β₂: t_{H_0}= \frac{b_2-\beta_2 }{Sb_2} t= 2.56; p-value: 0.0180 ⇒ Reject H₀, the test is significant.

β₃: t_{H_0}= \frac{b_3-\beta_3 }{Sb_3} t= 2.28; p-value: 0.0326 ⇒ Reject H₀, the test is significant.

e)

H₀: β₁= β₂= β₃

H₁: At least one βi is different from the others ∀ i=1, 2, 3

α: 0.05

F= 9.03

p-value: 0.0004

⇒ Reject H₀, the test is significant.

I hope it helps!

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egoroff_w [7]

Answer:

the anwser is B

Step-by-step explanation:

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