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Ulleksa [173]
3 years ago
8

Which is NOT proportionate to 15/45 3/9 3/15 1/3 30/90

Mathematics
1 answer:
ivann1987 [24]3 years ago
3 0
You would reduce each of them down by dividing both the top and bottom by the same number, so 15/45 turns into 1/3
3/9 - 1/3
3/15 - 1/5
1/3
30/90 - 1/3
The only one that's different is 3/15
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8 0
1 year ago
Imagine that you have entered the following distribution of scores into the program: 7, 9, 6, 3, 7, 8, 4, 10, 7, 9. The mean of
ozzi

Answer:

3

Step-by-step explanation:

Mean refers to the average value of the set of data.

It is the central value of the set of data.

Another word for Mean is average.

Given scores:7, 9, 6, 3, 7, 8, 4, 10, 7, 9

Solution:

Sum of observations = 7+ 9+ 6+ 3+ 7+ 8+ 4+ 10+ 7+ 9=70

Number of observations = 10

Mean = Sum of observations/Number of observations = \frac{70}{10}=7

If observation 3 is removed:

Sum of observations = 7+ 9+ 6+  7+ 8+ 4+ 10+ 7+ 9=67

Number of observations = 9

Mean =  Sum of observations/Number of observations = \frac{67}{9}=7.44

If observation 4 is removed:

Sum of observations = 7+ 9+ 6+ 3+ 7+ 8+ 10+ 7+ 9=66

Number of observations = 9

Mean = \frac{66}{9}=7.3

If observation 6 is removed:

Sum of observations = 7+ 9+ 3+ 7+ 8+ 4+ 10+ 7+ 9=64

Number of observations = 9

Mean = \frac{64}{9}=7.1

If observation 7 is removed:

Sum of observations = 9+ 6+ 3+  8+ 4+ 10+  9=49

Number of observations = 7

Mean = \frac{49}{7}=7

If observation 8 is removed:

Sum of observations = 7+ 9+ 6+ 3+ 7+  4+ 10+ 7+ 9=62

Number of observations = 9

Mean = \frac{62}{9}=6.9

If observation 9 is removed:

Sum of observations = 7+ 6+ 3+ 7+ 8+ 4+ 10+ 7=52

Number of observations = 8

Mean = \frac{52}{8}=6.5

If observation 10 is removed:

Sum of observations = 7+ 9+ 6+ 3+ 7+ 8+ 4+ 7+ 9=60

Number of observations = 9

Mean = \frac{60}{9}=6.7

Therefore, mean of this distribution of scores would be changed the most if a score 3 was removed from the data set.

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