Answer: y=|x-2|+3
Step-by-step explanation:
The height of the object after 1 sec is 284 feet
<h3>Equation of height of an object</h3>
Given the equation of height of an object expressed as:
h(t) = -16t^2 + 300t
We are to find the height of the object after 1 sec. To do that, we will substitute t = 1 into the following expression
h(t) = -16t^2 + 300t
h(1) = -16(1)^2 + 300(1)
h(1) = -16 + 300
h(1) = 284ft
Hence the height of the object after 1 sec is 284 feet
Learn more on maximum height here: brainly.com/question/12446886
Hey there!
2(6 * 4) + 2(6 * 2.4n) + 2(4 * 2.4n)
= 2(24) + 2(14.4n) + 2(9.6n)
= 48 + 28.8n + 19.2n
= 48 + 48n
= 48n + 48
Thus, your answer should be: 48n
Good luck on your assignment and enjoy your day!
~Amphitrite1040:)
You would use order or operations to solve this problem
4 to the second power is 16 -------> 12+16= 28
Your answer would be 28