A first order decomposition reaction has a half-life of 64yr. What percentage of the original amount is left after 135years. (gi
1 answer:
Answer:
23.2%
Step-by-step explanation:
First we need to find how many half lives 135 years is:
135 ÷ 64 = 2.109375
Now we divide 100% by 2 to the power of the number of half lives. This is how you calculate the percentage of the original amount left. If you have the original mass, you can substitute that in instead of 100%:
100 ÷ = 23.1747390635
To 1 decimal place it is 23.2%
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F(x) = (-x²+x+20) / (x+4)
-x²+x+20 | x+4
+x²+4x -x+5
\\\\ 5x+20
-5x-20
\\\\\\\\\
f(x) = (x+4)(-x+5) / (x+4)
f(x) = (-x+5)
The graph is a decreasing line, with origin from 5.
-x²+x+20 | x+4
+x²+4x -x+5
\\\\ 5x+20
-5x-20
\\\\\\\\\
f(x) = (x+4)(-x+5) / (x+4)
f(x) = (-x+5)
The graph is a decreasing line, with origin from 5.
The blue point on the number line is 5 units away from zero, which is: 5.
<h3>What is a Number Line?</h3>A number line is an arrangement of numbers from point zero, on both sides of the starting point, which is zero.
In the number line given, the blue point is 5 units away from the starting point, zero.
Therefore, the blue point is 5 on the number line.
Learn more about the number line on:
#SPJ1
