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Nataly_w [17]
4 years ago
13

Which type of element typically loses an electron to become an ion

Mathematics
2 answers:
Nat2105 [25]4 years ago
5 0

Answer:

The answer is B. Metal

Step-by-step explanation:

xenn [34]4 years ago
3 0
I think the answer is an atom
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Which function can be used to find the marked-up price of a marble countertop depending on the area?
kap26 [50]

Answer:

=4.8875a

Step-by-step explanation:

c(a) = 4.25 a

m(c) = 1.15c

We want to find m(c(a) )= 1.15(4.25a) =4.8875a

8 0
3 years ago
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Which expression is equivalent to (2x + 4)2 – (2x2 + 6)?
Anettt [7]

Answer:

The correct option is B). 2x^{2}+16x+10

Step-by-step explanation:

Given function is (2x+4)^{2}-(2x^{2} +6)

On simplifying,

=(2x+4)^{2}-(2x^{2} +6)

=[4x^{2}+16x+16]-(2x^{2} +6)

=4x^{2}+16x+16-2x^{2}-6

=2x^{2}+16x+10

Thus, The correct option is B). 2x^{2}+16x+10

8 0
3 years ago
Identify m∠CAR HELP ME ASAP!!
lord [1]

360 - 130 = 230

Measure of CAR = 230/2.

CAR = 115

5 0
3 years ago
A diver starts at the surface of the water and travels 8 feet to the bottom.
Sauron [17]

Answer:

On the graph B, at 0 seconds the graph will be <u>at y=0.</u>

The graph will be <u>going down</u> until 2 seconds, when the diver reaches her deepest point. At 2 seconds the height of the graph will be -8ft.

Step-by-step explanation:

In graph B we are measuring the distance from the surface, that is we are setting the surface to be y=0. Thus if the diver reaches her deepest point 8ft down, she will be below y=0 and at -8ft.

Thus, in shape the graph B will be similar to graph A, but it will be shifted downed by 8ft.

7 0
4 years ago
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Please help me answer this question
stealth61 [152]

The value of dy/dx for the functions are

(i) \frac{dy}{dx} = 4x^{2}sin2x.cos2x+ 2x. sin^{2}2x

(ii) \frac{dy}{dx} =\frac{- y(1+3x^{2})}{2x(1+x^{2}) }

<h3>Differentiation</h3>

From the question, we are to determine dy/dx for the given functions

(i) x^{2} sin^{2}2x

Let u = x^{2}

and

v = sin^{2} 2x

Also,

Let w=  sin2x

∴ v = w^{2}

First, we will determine \frac{dv}{dx}

Using the Chain rule
\frac{dv}{dx} = \frac{dv}{dw}.\frac{dw}{dx}

v = w^{2}

∴ \frac{dv}{dw} =2w

Also,

w=  sin2x

∴ \frac{dw}{dx} =2cos2x

Thus,

\frac{dv}{dx} = 2w \times 2cos2x

\frac{dv}{dx} = 2sin2x \times 2cos2x

\frac{dv}{dx} = 4sin2x . cos2x

Now, using the product rule

\frac{dy}{dx} = u\frac{dv}{dx} +  v\frac{du}{dx}

From above

u = x^{2}

∴ \frac{du}{dx}=2x

Now,

\frac{dy}{dx} = x^{2} (4sin2x.cos2x)+  sin^{2}2x (2x)

\frac{dy}{dx} = 4x^{2}sin2x.cos2x+ 2x. sin^{2}2x

(ii) xy^{2}+y^{2}x^{3} +2=0

Then,

x.2y\frac{dy}{dx}+ y^{2}(1)+y^{2}.3x^{2} + x^{3}.2y\frac{dy}{dx} +0=0

2xy\frac{dy}{dx}+ y^{2}+3x^{2}y^{2} + 2x^{3}y\frac{dy}{dx} =0

2xy\frac{dy}{dx}+2x^{3}y\frac{dy}{dx} =-  y^{2}-3x^{2}y^{2}

\frac{dy}{dx} (2xy+2x^{3}y)=-  y^{2}(1+3x^{2})

\frac{dy}{dx} =\frac{- y^{2}(1+3x^{2})}{2xy+2x^{3}y}

\frac{dy}{dx} =\frac{- y^{2}(1+3x^{2})}{2xy(1+x^{2}) }

\frac{dy}{dx} =\frac{- y(1+3x^{2})}{2x(1+x^{2}) }

Hence, the value of dy/dx for the functions are

(i) \frac{dy}{dx} = 4x^{2}sin2x.cos2x+ 2x. sin^{2}2x

(ii) \frac{dy}{dx} =\frac{- y(1+3x^{2})}{2x(1+x^{2}) }

Learn more on Differentiation here: brainly.com/question/24024883

#SPJ1

8 0
2 years ago
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