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iragen [17]
3 years ago
15

A diver starts at the surface of the water and travels 8 feet to the bottom.

Mathematics
2 answers:
pshichka [43]3 years ago
8 0

Answer:

On Graph B, at 0 seconds, the graph will be at 0 feet.

Then the graph will increase until 2 seconds, when the diver reaches her deepest point. At 2 seconds the height of Graph B will be at 8 feet.

Step-by-step explanation:

It just works.

Sauron [17]3 years ago
7 0

Answer:

On the graph B, at 0 seconds the graph will be <u>at y=0.</u>

The graph will be <u>going down</u> until 2 seconds, when the diver reaches her deepest point. At 2 seconds the height of the graph will be -8ft.

Step-by-step explanation:

In graph B we are measuring the distance from the surface, that is we are setting the surface to be y=0. Thus if the diver reaches her deepest point 8ft down, she will be below y=0 and at -8ft.

Thus, in shape the graph B will be similar to graph A, but it will be shifted downed by 8ft.

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Points H and F lie on circle c What is the length of line segment GH?
Nina [5.8K]

Answer:

6 units

Step-by-step explanation:

Given: Points H and F lie on  circle with center C. EG = 12, EC = 9 and ∠GEC = 90°.

To find: Length of GH.

Sol: EC = CH = 9 (Radius of the same circle are equal)

Now, GC = GH + CH

GC = GH + 9

Now In ΔEGC, using pythagoras theorem,

(Hypotenuse)^{2} = (Base)^{2} +(Altitude)^{2} ......(ΔEGC is a right triangle)

(GC)^{2} = (GE)^{2} +(EC)^{2}

(GH + 9)^{2} = (9)^{2} +(12)^{2}

(GH )^{2} + (9)^{2} + 18GH = 81 + 144

(GH )^{2} + 81 + 18GH = 81 + 144

(GH )^{2} + 18GH = 144

Now, Let GH = <em>x</em>

x^{2} +18x = 144

On rearranging,

x^{2} +18 x - 144 = 0

x^{2} - 6x +24x + 144 = 0

x (x-6) + 24 (x - 6) =0

(x - 6) (x + 24) = 0

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Therefore, the length of line segment GH = 6 units. so, Option (D) is the correct answer.

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