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iragen [17]
3 years ago
15

A diver starts at the surface of the water and travels 8 feet to the bottom.

Mathematics
2 answers:
pshichka [43]3 years ago
8 0

Answer:

On Graph B, at 0 seconds, the graph will be at 0 feet.

Then the graph will increase until 2 seconds, when the diver reaches her deepest point. At 2 seconds the height of Graph B will be at 8 feet.

Step-by-step explanation:

It just works.

Sauron [17]3 years ago
7 0

Answer:

On the graph B, at 0 seconds the graph will be <u>at y=0.</u>

The graph will be <u>going down</u> until 2 seconds, when the diver reaches her deepest point. At 2 seconds the height of the graph will be -8ft.

Step-by-step explanation:

In graph B we are measuring the distance from the surface, that is we are setting the surface to be y=0. Thus if the diver reaches her deepest point 8ft down, she will be below y=0 and at -8ft.

Thus, in shape the graph B will be similar to graph A, but it will be shifted downed by 8ft.

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Given : Radius of cylinder = 8 m

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Curved surface area = 2πrh sq. units

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Total surface area = 2πr(r + h) sq. units

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= 2 × 22/7 × 8 × 12 m²

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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3 years ago
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Answer:

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