Minimum is (4,3) and Vertical intercept is (0,5) correct me if I’m wrong
Answer: David made 120 drawings while at summer camp
Answer:
x is equal to 0.94 and -1.94
Step-by-step explanation:
3x² + 3x + 7 = 0
9x² + 9x + 21 = 0
9x² + 9x + 2.25 = 18.75
(3x + 1.5)² = 18.75
3x + 1.5 = ±√18.75
3x = -1.5 ±√18.75
x = (-1.5 ±√18.75) / 3
x = 0.94, -1.94
Initial velocity of the plane is Vo = 0.
acceleration a = 1.3 m/s2
total distance = 2.5 km = 2500m
time taken to reach 2.5 km with 1.3m/s^2 acceleration = t
S = Vo t + 0.5 a t^2
2500 = 0 + (0.5*1.3* t^2)
t^2 = 3846.15
t = 62 s
the maximum velocity plan can reach within 62 s is Vt
Vt = Vo + a t
Vt = 0 + (1.3*62)
Vt = 80.6 m/s
Since 80.6 m/s is greater than 75 m/s, plane can use this runway to takeoff with required speed.
Answer:
what is the questions
Step-by-step explanation:
