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iren2701 [21]
2 years ago
7

You are making identical bagel platters using 40 plain bagels, 30 raisin bagels, and 24 blueberry bagels. what is the greatest n

umber of platters that you can make if there are no leftover bagels?
Mathematics
2 answers:
irina [24]2 years ago
8 0

Answer:

nope nope nope nope nope nope nope nope nope nope nope nope nope

Step-by-step explanation:

nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope nope

Marat540 [252]2 years ago
4 0

Answer:

100

Step-by-step explanation:

94 bagels in total. 100 will be plenty

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Hjgsjgsjgek zhfsurznf. Bsyeruqkhckh sjgwkgeidkgegkw jaws
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2 years ago
What is the volume of the composite figure shown below?
AVprozaik [17]

Answer:

2412 mm³

Step-by-step explanation:

In the figure attached, the composite figure is shown.

Dimension of top rectangular prism:

  • length of 13 millimeters
  • width of 12 millimeters
  • height of 12 millimeters

Volume of top rectangular prism: length*width*height = 13*12*12 = 1872 mm³

Dimension of bottom rectangular prism:

  • length of 15 millimeters
  • width of 12 millimeters
  • height of 3 millimeters

Volume of bottom rectangular prism: length*width*height = 15*12*3 = 540 mm³

Volume of the composite figure: 1872 + 540 = 2412 mm³

7 0
2 years ago
Four cards are dealt from a standard fifty-two-card poker deck. What is the probability that all four are aces given that at lea
elena-s [515]

Answer:

The probability is 0.0052

Step-by-step explanation:

Let's call A the event that the four cards are aces, B the event that at least three are aces. So, the probability P(A/B) that all four are aces given that at least three are aces is calculated as:

P(A/B) =  P(A∩B)/P(B)

The probability P(B) that at least three are aces is the sum of the following probabilities:

  • The four card are aces: This is one hand from the 270,725 differents sets of four cards, so the probability is 1/270,725
  • There are exactly 3 aces: we need to calculated how many hands have exactly 3 aces, so we are going to calculate de number of combinations or ways in which we can select k elements from a group of n elements. This can be calculated as:

nCk=\frac{n!}{k!(n-k)!}

So, the number of ways to select exactly 3 aces is:

4C3*48C1=\frac{4!}{3!(4-3)!}*\frac{48!}{1!(48-1)!}=192

Because we are going to select 3 aces from the 4 in the poker deck and we are going to select 1 card from the 48 that aren't aces. So the probability in this case is 192/270,725

Then, the probability P(B) that at least three are aces is:

P(B)=\frac{1}{270,725} +\frac{192}{270,725} =\frac{193}{270,725}

On the other hand the probability P(A∩B) that the four cards are aces and at least three are aces is equal to the probability that the four card are aces, so:

P(A∩B) = 1/270,725

Finally, the probability P(A/B) that all four are aces given that at least three are aces is:

P=\frac{1/270,725}{193/270,725} =\frac{1}{193}=0.0052

5 0
3 years ago
<img src="https://tex.z-dn.net/?f=x%20%2B%20y%20%20%3D%2014%5C%5C%202x%20%2B%204y%20%3D%2018" id="TexFormula1" title="x + y = 1
alexgriva [62]

Answer:

x = 19, y = -5

Step-by-step explanation:

x + y = 14  => x= 14-y

2x + 4y = 18  => 2(x+2y)=18  => x+2y=9

x+2y=9 => (14 - y) + 2y = 9

14 + y = 9  => y = -5

x + (-5) = 14  => x=19

5 0
2 years ago
Consider the original complex figure and the reduction.
Dmitriy789 [7]

Answer:

1/8

Step-by-step explanation:

I'm going to try to explain this as easy as possible. What I did was take the original shape and divide it by the new shape. For this question, I solved it by dividing 32(the original base) by 4(the new base) and got 8. So the scale factor of the reduction was 1/8.

8 0
2 years ago
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