The 3-digit number is 132
<h3>How to determine the
3-digit number?</h3>
The given parameters are:
- Number of digits = 3
- Sum of digits = 6
- No 0s in the number
- No repeated digit
The first highlight above implies that the number can be any of 100 to 999
The other highlights imply that the no digit can appear repeatedly, the highest digit in the number is 3, and the number must end with 2.
So, we have:
X32
The first digit is the smallest.
1 is smaller than 3 and 2.
So, we have
132
Hence, the 3-digit number is 132
Read more about digits and numbers at:
brainly.com/question/26856218
#SPJ1
Answer:
hindi po maintindihan yung tanong nyo po
.50 x 2 < .20 x 100
1 < 20
50% of 2 is not greater than 20% of 100.
Answer:
So, for the ascending order, there are only 9 digits to choose from, and hence, there are 9C5 ways to choose the 5 digits. So, there can be 9C5=126 5-digit no.s with their digits in an ascending order.
126 5
Answer:
h=
Step-by-step explanation:
1.) You must isolate the h from the equation by dividing both sides by L (or multiply by its reciprocal, which in this case, the reciprocal on L is 
.....So it would look like:
2.) Simplify the equation if you need to (in this case, its not needed)
That's your answer :)
