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lisov135 [29]
3 years ago
9

Please help with this question.

Mathematics
1 answer:
Rzqust [24]3 years ago
4 0
(cos Ф -cos Ф)² + (cos Ф + cos Ф)²

Firstly: (cos Ф -cos Ф)² = 0² = 0

Secondly :(cos Ф + cos Ф)² = (2cos Ф)². = 4. (cos Ф)² = 4cos² Ф

Mind you when you raise a cosine (or sin or tan...) to the n power, the n power should affect the cosine only and NOT the angle Ф

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Elapsed time five in the afternoon to 1 minute after midnight​
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Answer:

The elapsed time is 7hrs and 1 minute.

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In a normal distribution, 99.7% of the data fall within how many standard
Mazyrski [523]

Answer: Three standard deviation

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
It costs $60 to buy 10 hamburgers. At this rate, how much would it cost to buy 12 hamburgers? (Use proportions to help you).
MrRa [10]

Answer:

72

Step-by-step explanation:

I divided.$60 by 10 and got $6 per every burger, then I multiplied $6 x 12 and got $72.

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PLS HELP WITH THIS QUESTION
seropon [69]

Answer:

Around 37, first one

Step-by-step explanation:

add up all the 7th grader number, 40

125 divided by 40 is around 3.125

3.125 times 12 = 37.5

37 because there is no half a kid

3 0
3 years ago
I WILL GIVE YOU 40 POINTS PLEASE HELP<br> (2)/(x^2-9) - (3x)/( x^2-5x+6) please show work
mars1129 [50]

Answer:

\frac{-3x^2-7x-4}{x^3-2x^2-9x+18}

Step-by-step explanation:

\frac{2}{x^2-9}-\frac{3x}{x^2-5x+6}

Factor x²-9 and x²-5x+6.

\frac{2}{\left(x+3\right)\left(x-3\right)}-\frac{3x}{\left(x-2\right)\left(x-3\right)}

Least common multiple of (x+3), (x-3), (x-2), and (x-3) is (x+3), (x-3), and (x-2).

Adjust the fractions based on LCM.

\frac{2\left(x-2\right)}{\left(x+3\right)\left(x-3\right)\left(x-2\right)}-\frac{3x\left(x+3\right)}{\left(x-2\right)\left(x-3\right)\left(x+3\right)}

Subtract the fractions since denominators are equal.

\frac{2\left(x-2\right)-3x\left(x+3\right)}{\left(x+3\right)\left(x-3\right)\left(x-2\right)}

Expand.

\frac{-3x^2-7x-4}{x^3-2x^2-9x+18}

The fraction can be in factored form.

\frac{-\left(x+1\right)\left(3x+4\right)}{\left(x-2\right)\left(x+3\right)\left(x-3\right)}

4 0
4 years ago
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