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Delvig [45]
3 years ago
6

Drius Security stock has a yearly dividend of $12.11. If you own 132 shares of Drius Security, how much do you get paid in quart

erly dividends? a. $133.21 b. $1,598.52 c. $366.96 d. $399.63
Mathematics
2 answers:
aivan3 [116]3 years ago
5 0

Dividends are paid per share. So $12.11 per year is paid per share.

So, if you own 132 shares, you get 132*12.11=1598.52 dollars per year for all the stocks.

<em>A quarter is \frac{1}{4} of a year. </em>

So, you would be expected to get \frac{1}{4}*1598.52=399.63 dollars in quarterly dividends. Answer choice D is correct.


ANSWER: D

Allushta [10]3 years ago
4 0

Answer:

The correct answer is D.) $399.63

Step-by-step explanation: Just took the test and got every answer right on edg.

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Jim drives his children to their sports activities outside of school. When he drives his son to baseball practice, it is a 6-km
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Answer:

17.4 kilometers per week

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we know that

The number of kilometers that Jim drives a week is equal to the number of baseball practice multiplied by its round trip plus the number basketball practice multiplied by its round trip

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6 0
3 years ago
A jar contains chocolate candies. There are 12 red, 17 blue, 5 green and 6 orange. What is the probability of picking either a g
nataly862011 [7]

Answer:

Step-by-step explanation:

If you sum everything, you'll get 50 candies. Now you know that 50 candies is 100%.

Now you'll calculate the probability:

12 on 50 : 24.00 %

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Edit :

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7 0
3 years ago
Let X denote the distance (m) that an animal moves from its birth site to the first territorial vacancy it encounters. Suppose t
andrezito [222]

Answer and Step-by-step explanation: For an exponential distribution, the probability distribution function is:

f(x) = λ.e^{-\lambda.x}

and the cumulative distribution function, which describes the probability distribution of a random variable X, is:

F(x) = 1 - e^{-\lambda.x}

(a) <u>Probability</u> of distance at most <u>100m</u>, with λ = 0.0143:

F(100) = 1 - e^{-0.0143.100}

F(100) = 0.76

<u>Probability</u> of distance at most <u>200</u>:

F(200) = 1 - e^{-0.0143.200}

F(200) = 0.94

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F(100≤X≤200) = F(200) - F(100)

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E(X) = \frac{1}{\lambda}

E(X) = \frac{1}{0.0143}

E(X) = 69.93

The standard deviation is the square root of variance,V(X), which is calculated by:

σ = \sqrt{\frac{1}{\lambda^{2}} }

σ = \sqrt{\frac{1}{0.0143^{2}} }

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(c) Median is a point that divides the value in half. For a probability distribution:

P(X≤m) = 0.5

\int\limits^m_0 f({x}) \, dx = 0.5

\int\limits^m_0 {\lambda.e^{-\lambda.x}} \, dx = 0.5

\lambda.\frac{e^{-\lambda.x}}{-\lambda} = -e^{-\lambda.x} + e^{0}

1 - e^{-\lambda.m} = 0.5

-e^{-\lambda.m} = - 0.5

ln(e^{-0.0143.m}) = ln(0.5)

-0.0143.m = - 0.0693

m = 48.46

6 0
3 years ago
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Answer:

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Step-by-step explanation:

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