Answer:
The answer is b. Carbon Tetrachloride
Explanation:
Let's discard the other options:
a. It couldn't be carbon chloride because there are four (4) chloride ions in the molecular formula. The molecular formula for the carbon chloride must be CCI. So, this answer is wrong
c. It could be monocarbon tetrachloride because there are 4 chloride ions and 1 carbon ion, but it's not necessary to use the prefix "mono" because there is just one carbon ion in the formula. In that way, when we mention carbon in the name, there is implicit that there is just one carbon atom in the formula. So, this answer could be ok, but isn't the best.
d. It couldn't be calcium chloride because there isn't any calcium ion or atom in the formula. The molecular formula for the calcium chloride must be CaCI. So, this answer is wrong
A. hex- Normally with 6, the prefix is hex-. For example a polygon having 6 sides is known as hexagon.
Answer:
C) cation, loses, anion, gains
Explanation:
Lithium is a metal from Group 1, so it has 1 valence electron. Thus, it loses 1 electron to complete its octet and form the cation Li⁺.
Oxygen is a nonmetal from Group 16, so it has 6 valence electrons. Thus, it gains 2 electrons to complete its octet and form the anion O²⁻.
In the reaction between Li and O, there is a transfer of electrons making an ionic bond. In the bond, lithium would be a cation because it loses an electron, and oxygen would be an anion because it gains 2 electrons.
Answer:
The order of reaction is 2.
Rate constant is 0.0328 (M s)⁻¹
Explanation:
The rate of a reaction is inversely proportional to the time taken for the reaction.
As we are decreasing the concentration of the reactant the half life is increasing.
a) For zero order reaction: the half life is directly proportional to initial concentration of reactant
b) for first order reaction: the half life is independent of the initial concentration.
c) higher order reaction: The relation between half life and rate of reaction is:
Rate = ![\frac{1}{k[A_{0}]^{(n-1)}}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7Bk%5BA_%7B0%7D%5D%5E%7B%28n-1%29%7D%7D)
Half life =![K\frac{1}{[A_{0}]^{(n-1)} }](https://tex.z-dn.net/?f=K%5Cfrac%7B1%7D%7B%5BA_%7B0%7D%5D%5E%7B%28n-1%29%7D%20%7D)
![\frac{(halflife_{1})}{(halflife_{2})}=\frac{[A_{2}]^{(n-1)}}{[A_{1}]^{(n-1)} }](https://tex.z-dn.net/?f=%5Cfrac%7B%28halflife_%7B1%7D%29%7D%7B%28halflife_%7B2%7D%29%7D%3D%5Cfrac%7B%5BA_%7B2%7D%5D%5E%7B%28n-1%29%7D%7D%7B%5BA_%7B1%7D%5D%5E%7B%28n-1%29%7D%20%7D)
where n = order of reaction
Putting values
![\frac{109}{231}=\frac{[0.132]^{(n-1)}}{[0.280]^{(n-1)}}](https://tex.z-dn.net/?f=%5Cfrac%7B109%7D%7B231%7D%3D%5Cfrac%7B%5B0.132%5D%5E%7B%28n-1%29%7D%7D%7B%5B0.280%5D%5E%7B%28n-1%29%7D%7D)

Hence n = 2
![halflife=\frac{1}{k[A_{0}]}](https://tex.z-dn.net/?f=halflife%3D%5Cfrac%7B1%7D%7Bk%5BA_%7B0%7D%5D%7D)
Putting values

K = 0.0328
Answer:
a. 41 mg equals 0.041 grams.
b. 41 mg equals 0.0014462 ounces
c. 41 mg equals 9.039*10⁻⁵ pounds
Explanation:
You know that a slice of Swiss cheese contains 41 mg of sodium.
a. What is this mass in grams?
Knowing that 1 mg = 10⁻³ g, you can apply the following rule of three: if 1 mg equals 10⁻³ g or 0.001 grams, 41 mg will be equivalent to how much mass in g?

mass= 0.041 grams
<u><em>
41 mg equals 0.041 grams.</em></u>
b. What is this mass in ounces?
Knowing that 1 mg = 3.5274 * 10⁻⁵ ounces, you can apply the following rule of three: if 1 mg equals 3.5274 * 10⁻⁵ ounces, 41 mg will be equivalent to how much mass in ounces?

mass= 1.4462*10 ⁻³ ounces= 0.0014462 ounces
<u><em>41 mg equals 0.0014462 ounces</em></u>
c. What is this mass in pounds?
Knowing that 1 mg = 2.20462 * 10⁻⁶ pounds, you can apply the following rule of three: if 1 mg equals 2.20462 * 10⁻⁶ pounds, 41 mg will be equivalent to how much mass in pounds?

mass= 9.039*10⁻⁵ pounds
<u><em>41 mg equals 9.039*10⁻⁵ pounds</em></u>