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Maurinko [17]
2 years ago
15

How is the kinetic energy of the constituent particles of any matter affected by a change in temperature?

Chemistry
1 answer:
SpyIntel [72]2 years ago
5 0

Answer:

Particles in all states of matter are in constant motion and this is very rapid at room temperature. A rise in temperature increases the kinetic energy and speed of particles; it does not weaken the forces between them. ... Individual particles in liquids and gases have no fixed positions and move chaotically.

Explanation:

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1. the purpose of the aqueous solutions in a galvanic cell is to?
ludmilkaskok [199]

Answer:

1. The correct option is;

c. maintains charge balance in the cell

2. The correct option is;

c. +3.272 V

Explanation:

The aqueous solution in a galvanic cell is the electrolyte which is a ionic solution containing that permits the transfer of ions between the separated compartment of the galvanic cell such that the overall system is electrically neutral

Therefore, the aqueous solution maintains the charge balance in the cell

2. Here we have;

B₂ + 2e⁻ → 2B⁻ Ecell = 0.662 V

A⁺ + 1e⁻ → A Ecell = -1.305 V

Hence for the overall reaction, we have;

2A + B₂ → 2AB gives;

(0.662) - 2×(-1.305)  = +3.272 V.

4 0
3 years ago
What formula gives the ratio of elements?
USPshnik [31]

Answer:

In a chemical formula, the elements in a compound are represented by their chemical symbols, and the ratio of different elements is represented by subscripts.

Explanation:

6 0
2 years ago
How many liters are in a 0.115 M solution containing 1.55 moles of dissolved KBr?
Anika [276]
13.48 is your answer.

M=moles/liters we have M=.115 and moles=1.55

Input those values into the equation
.115=1.55/L

Solve for L
1.55/.115=13.48
5 0
2 years ago
How many atoms are in 15 grams of H2O
gulaghasi [49]

Answer:

5.014x10^23 atoms

Explanation:

first start with given over 1 so 15 over 1 then multiply that by 1 over 18.01528 and then multiply it by 6.022x10^23 over 1 which then gives you the answear hope this helps god bless

4 0
3 years ago
If a chemist wants to make 1.3 L of 0.25 M solution of KOH by diluting a stock solution of 0.675 M KOH, how many milliliters of
anzhelika [568]

To solve this we use the equation,

 

M1V1 = M2V2

 

where M1 is the concentration of the stock solution, V1 is the volume of the stock solution, M2 is the concentration of the new solution and V2 is its volume.

 

.675 M x V1 = .25 M x 1.3 L

V1 = 0.48 L or 480 mL

8 0
3 years ago
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