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bagirrra123 [75]
3 years ago
13

How does the chemical formula for the sulfite ion differ from the chemical formula for the sulfate ion?

Chemistry
1 answer:
VLD [36.1K]3 years ago
6 0

Answer:

Sulfite contains 3 oxygens and sulfate contains 4 oxygens

Explanation:

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IS IT BETTER OR WORSE TO WORKOUT/EXERCISE IN DARK OR LIGHT COLORED CLOTHING? ​
soldi70 [24.7K]

Answer:

Dark clothing

Explanation:

Dark clothing like black absorbs/locks in heat. Since exercise is to burn and tonify our body from unwanted fat it is important to sweat. This is where heat comes in and helps you sweat

3 0
2 years ago
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Can you explain so I can understand
Art [367]
It would be insulator because an insulator kills electricity, it can't travel through it. 
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3 years ago
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How do you know a physical change has occurred when evaporating water produces gaseous water?
levacccp [35]

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Its b its the state not anything else

6 0
3 years ago
WS Percent yield don’t understand how to do would appreciate the help
Grace [21]

Answer:

1. Theoretical yield of NaOH is 22.72 g

2. Percentage yield of NaOH = 22.14%

Explanation:

We'll begin by writing the balanced equation for the reaction. This is illustrated below:

NaHCO₃ —> NaOH + CO₂

From the balanced equation above,,

1 mole of NaHCO₃ decomposed to produce 1 mole (i.e 40 g) of NaOH and 1 mole (i.e 44.01 g) of CO₂.

Next, we shall determine the number of mole of NaHCO₃ that will decompose to produce 25 g of CO₂. This can be obtained as follow:

From the balanced equation above,,

1 mole of NaHCO₃ decomposed to produce 44.01 g of CO₂.

Therefore, Xmol of NaHCO₃ will decompose to 25 g of CO₂ i.e

Xmol of NaHCO₃ = 25 / 44.01

Xmol of NaHCO₃ = 0.568 mole

1. Determination of the theoretical yield of NaOH.

From the balanced equation above,,

1 mole of NaHCO₃ decomposed to produce 40 g of NaOH.

Therefore, 0.568 mole of NaHCO₃ will decompose to produce = 0.568 × 40 = 22.72 g of NaOH.

Thus, the theoretical yield of NaOH is 22.72 g

2. Determination of the percentage yield of NaOH.

Theoretical yield of NaOH = 22.72 g

Actual yield of NaOH = 5.03 g

Percentage yield of NaOH =?

Percentage yield = Actual yield /Theoretical yield × 100

Percentage yield = 5.03 / 22.72 × 100

Percentage yield of NaOH = 22.14%

4 0
2 years ago
The percent composition by mass of magnesium MgBr2 (gram formula mass= 184 grams/mole) is equal to...
k0ka [10]
The percent composition by mass of an element is determined by dividing the molar mass of the element by the molar mass of the compound. In this case, the molar mass of magnesium is 24. Hence the answer to this problem is A. 24/184 x 100
4 0
3 years ago
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