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Ksju [112]
3 years ago
12

A plant grows 12 mm every four months how many centimeters will it grow in one year?

Mathematics
1 answer:
swat323 years ago
7 0

Step-by-step explanation:

One year is 12 months.  12 mm is 1.2 cm.

Write and solve a proportion

1.2 cm / 4 months = x / 12 months

x = 3.6 cm

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48 is the product of Carlos's age and 3.
Sergio [31]

Answer:

16

Step-by-step explanation:

48= 3x

48/3 = x

x= 16

'product and' means multiply I googled it

7 0
3 years ago
Please help solve quick
RoseWind [281]

Answer:

see below

Step-by-step explanation:

3x^2 + 17x +10 =0

(3x+   ) ( x+   ) =0

We need to factor 10  = 2*5  or 1*10

They are positive since we have all positive terms

3*5 = 15+2 = 17

The 5 needs to multiply the 3 so it goes on the outside

(3x+   ) ( x+  5 ) =0

That leaves the 2 on the inside

(3x+ 2  ) ( x+ 5  ) =0

Using the zero product property

3x+2 =0     x+5=0

3x = -2          x=-5

x = -2/3          x = -5

5 0
3 years ago
How to solve this question? Please help me
Maurinko [17]

Answer:

≈ 82 feet

Step-by-step explanation:

Since the triangle is right use Pythagoras' identity to calculate distance (d)

The square on the hypotenuse is equal to the sum of the squares on the other 2 sides.

Here the hypotenuse is the distance (d) between the 2 poles, hence

d² = 80² + 45² = 6400 + 2025 = 8425 ( take the square root of both sides )

d = \sqrt{8425} ≈ 82 feet ( to the nearest foot )

8 0
3 years ago
Use Hooke's Law to determine the work done by the variable force in the spring problem. A force of 450 newtons stretches a sprin
vlada-n [284]

Answer:

The work done is 202.50Nm

Step-by-step explanation:

Given

F =450N

x_1 = 30cm

x_2 = 60cm

Required

The work done

First, we calculate the spring constant (k)

F = kx_1

450N = k *30cm

k = \frac{450N}{30cm}

k =15N/cm

So:

F = kx_1

F(x) = 15x

The work done using Hooke's law is:

W =\int\limits^a_b {F(x)} \, dx

This gives:

W =\int\limits^{60}_{30} {15x} \, dx

Rewrite as:

W =15\int\limits^{60}_{30} {x} \, dx

Integrate

W =15 \frac{x^2}{2}|\limits^{60}_{30}

This gives:

W =15 *\frac{60^2 - 30^2}{2}

W =15 *\frac{2700}{2}

W =15 *1350

W =20250N-cm

Convert to Nm

W =\frac{20250Nm}{100}

W =202.50Nm

7 0
3 years ago
[(51 + 3) − 32] ÷ 9 ⋅ 2.
galina1969 [7]
Your answer is 4.88 using PEMDAS

7 0
3 years ago
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