The point G on AB such that the ratio of AG to GB is 3:2 is; G(4.2, 2)
How to partition a Line segment?
The formula to partition a line segment in the ratio a:b is;
(x, y) = [(bx1 + ax2)/(a + b)], [(by1 + ay2)/(a + b)]
We want to find point G on AB such that the ratio of AG to GB is 3:2.
From the graph, the coordinates of the points A and B are;
A(3, 5) and B(5, 0)
Thus, coordinates of point G that divides the line AB in the ratio of 3:2 is;
G(x, y) = [(2 * 3 + 3 * 5)/(2 + 3)], [(2 * 5 + 3 * 0)/(2 + 3)]
G(x, y) = (21/5, 10/5)
G(x, y) = (4.2, 2)
Read more about Line segment partition at; brainly.com/question/17374569
#SPJ1
Answer:
x < 3
Step-by-step explanation:
tell you teacher to Fu** off
Turning points are inflection points
think
1st degree (linear) has no turning/inflecion points
2nd degree (quadratic, parabola) has 1 turning/inflection point
so
nth degree has n-1 turning/inflection point
this is 11th degree since highest power is 12
12-1=11
11 turning oints
Answer:
The 
, 
and 
.
Step-by-step explanation:
The given function is
.... (1)
The general form of sine function is
....(2)
where, |A| is the amplitude, B is period, D is the vertical shift (up or down), and C/B is used to find the phase shift.
On comparing (1) and (2), we get
So,
Therefore , and .
