Question

Find the area (PLEASE HELP DUE SOON!!! thanks xo)

Answer 1

Answer:

The total area of the rocket is = 44

Step-by-step explanation:

a) shape 1 is a triangle

Base = 3 and height = 4

A = 1/2bh

A = 1/2 × 3 × 4

A = 3 × 2 = 6

b) shape 2 is a rectangle

Length = 10 and width = 3

A = l × w

A = 10 × 3

A = 30

c) shape 3 is a trapezium

a = 3, b = 5, h = 2

A = 1/2(a + b)h

A = 1/2(3 + 5) 2

A = 1/2 (8) 2

A = 8

d) total area of the rocket = Area of shape 1 + area of shape 2 + area of shape 3

Total area = 6 + 30 + 8

= 44

Answer 2

Area of shape 1 = 6 sq unit

Area of shape 2 = 30 sq unit

Area of shape 3 = 8 sq unit

Area of rocket = 44 sq unit

Step-by-step explanation:

The rocket consists if 3 shapes : triangle, rectangle and trapezium

Area of the triangle  = $\frac{1}{2}$ X 3 X 4 = 6 sq unit [ base = 3 and height = 4]

Area of the rectangle = 10 X 3 = 30 sq unit [ length = 10 and width = 3]

Area of the trapezium = $\frac{1}{2}$ X ( a+b) x h [ a= 3 b= 5 and h= 2]

= $\frac{1}{2}$ X 8 X 2 = 8 sq unit

Hence, area of the square = 6 + 30 + 8 = 44 sq unit