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2 years ago

3 + 3(k + 3) = 6(k - 2) +9

Mathematics

1 answer:

ANTONII [103]2 years ago

7 0

Step-by-step explanation:

3 + 3(k + 3) = 6(k - 2) + 9

3 + 3k + 9 = 6k - 12 + 9

12 + 12 - 9 = 6k - 3k

15 = 3k

k = 15/3

k = 5

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Given,

$F(x,y,z)=yz \uvec i +xz\uvec j+(xy+6z)\uvex k$

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$F(x,y,z)=yz \uvec i +xz\uvec j+(xy+6z)\uvex k=f_x \uvec{i} +f_y \uvex{j}+f_z\uvec{k}$

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$f(x,y,z)=xyz+g(y,z)$

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$f_y=xz+g'(y,z)$

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$g'(y,z)=0\implies g(y,z)=0+h(z)\implies g(y,z)=h(z)$

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$f(x,y,z)=xyz+h(z)$

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$f_z=xy+h'(z)=xy+6z$

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3 years ago

3 + 3(k + 3) = 6(k - 2) +9​

3 + 3(k + 3) = 6(k - 2) +9