This must be on the moon as the acceleration due to gravity in this equation must be around 1/8 that on earth. :) Anyway...
h=-2t^2+9t+11
A)
dh/dt=-4t+9, when velocity, dh/dt=0, it is the maximum height reached
dh/dt=0 only when 4t=9, t=2.25 seconds
h(2.25)=21.125 ft (21 1/8 ft)
B)
As seen in A), the time of maximum height was 2.25 seconds after the squirrel jumped.
C)
The squirrel reaches the ground when h=0...
0=-2t^2+9t+11
-2t^2-2t+11t+11=0
-2t(t+1)+11(t+1)=0
(-2t+11)(t+1)=0, since t>0 for this problem...
-2t+11=0
-2t=-11
t=5.5 seconds.
So.. both sides divided by 4.
Now u have 14/68=x/6 -5
Multiply all by 6
Now u have 84/68=x-30
21/17+510/17=x
531/17=x
X=31 4/17
Answer:
40%
Step-by-step explanation:
38×100=3800÷95=40
40%×95=38
A.) y= 5/4x+16
B.) 1.25 hours a day
