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3 years ago

What is the 7.35 percent of 71.00 dollars

Mathematics

2 answers:

juin [17]3 years ago

4 0

$65.78 Multiply 7.35% x 71 Then subtract 5.22 from 71 and you get 65.78

SSSSS [86.1K]3 years ago

3 0

5.22 dollars is what I got any body do anything different

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Which expression is the correct translation of the following word phrase?

Llana [10]

Hey, there!

The parentheses would make it multiplication
The word sum means add
A number was unknown, so we will label it as "x"

So, let's see what we're working with here!

If you chose "Option A" the question would be "five multiplied by a number and the sum of 3" (that doesn't give you the right answer"
For B. same thing with option A
For "Option C" its not asking you "a number with sum of three times five"

So, this leaves "Option D." as your answer because 3 is getting multiplied by the sum of some number and five

Good luck on your assignment and enjoy your day!

~MeIsKaitlyn:)

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3 years ago

Karen makes 9 dollars for each hour of work. Write an equation to represent her total pay p after working hours.

Makovka662 [10]

Let the number of hours she work be n
So the equation will be
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3 years ago

Tyler is offered to choose between three boxes that look identical. The first box contains 1 red pills and 19 blue pills, the se

Dafna1 [17]

Answer:

A) 0.15

B) 0.36

Step-by-step explanation:

First Box consist 1 red pills and 19 blue pills

second box consist 6 red pills and 14 blue pills

Third box consist 2 red pills and 18 blue pills

a) Prob ( randomly chosen pill is red) $= \frac{1}{3} \times \frac{1}{20} + \frac{1}{3} \times \frac{6}{20} + \frac{1}{3} \times \frac{2}{20}$

$\frac{1}{60} (1+6+2) = 0.15$

b)Prob ( 1 reds and 10 blue pilss) = $\frac{1}{3} \frac{^1C_1\times ^{19}C_{10}}{^{20}C_{11}} + \frac{1}{3} \frac{^6C_1\times ^{14}C_{10}}{^{20}C_{11}} + \frac{1}{3} \frac{^2C_1\times ^{18}C_{10}}{^{20}C_{11}}$

$= \frac{1}{3} 1.106 = 0.368$

7 0

3 years ago

A story about the doubles plus 2 fact 5+7

miss Akunina [59]

The answer is 12 because 5+7=12

8 0

3 years ago

Three fair coins are tossed. If all land "heads," the player wins $10, and if exactly two land heads, the player wins $5. If it

hodyreva [135]

Answer:

After four games, a player can lose up to $ 16 to win up to $ 26. These are the probabilities for every game:

1/8 or 12.5% of landing three "heads"

3/8 or 37.5% of landing two "heads"

4/8 or 50% of landing no or only one "head".

Step-by-step explanation:

1. Let's review the information given to us to answer the question correctly:

If three coins land "heads" the player wins $ 10

If two coins land "heads" the player wins $ 5

Cost of playing = $ 4

2. What is the player's expected outcome after four games?

Probability of two coins out of three lands "heads" = 3/8

Probability of three coins out of three lands "heads" = 1/8

Now, let's calculate the player's expected outcome, as follows:

Four games:

Cost = 4 * 4 = $ 16

Worst-case scenario: No wins

Best-case scenario: 4 out of 4 of $ 10 win

Worst-case scenario profit or loss = 0 - 16 = Loss of $ 16

Best-case scenario profit or loss = 40 - 16 = Profit of $ 24

After four games, a player can lose up to $ 16 to win up to $ 26. These are the probabilities for every game:

1/8 or 12.5% of landing three "heads"

3/8 or 37.5% of landing two "heads"

4/8 or 50% of landing no or only one "head".

8 0

3 years ago