Answer:
<h2>SEE BELOW</h2>
Step-by-step explanation:
<h3>to understand this</h3><h3>you need to know about:</h3>
<h3>let's solve:</h3>
vertex:(h,k)
therefore
vertex:(-1,4)
axis of symmetry:x=h
therefore
axis of symmetry:x=-1
- to find the quadratic equation we need to figure out the vertex form of quadratic equation and then simply it to standard form i.e ax²+bx+c=0
vertex form of quadratic equation:
therefore
- y=a(x-(-1))²+4
- y=a(x+1)²+4
it's to notice that we don't know what a is
therefore we have to figure it out
the graph crosses y-asix at (0,3) coordinates
so,
3=a(0+1)²+4
simplify parentheses:

simplify exponent:

therefore

our vertex form of quadratic equation is
let's simplify it to standard form
simplify square:

simplify parentheses:

simplify addition:

therefore our answer is D)y=-x²-2x+3
the domain of the function

and the range of the function is

zeroes of the function:




factor out x and -1 respectively:

group:

therefore

The solution to the system of linear equations is where the two lines intersect.
Look for the point where the two lines intersect. The x-value is 2 1/2, and the y-value is -4.
The answer is C.
From the description given for the triangle above, I think the type of triangle that is represented would be a right triangle. This type of triangle contains a right angle and two acute angles. In order to say or prove that it is a right triangle, it should be able to satisfy the Pythagorean Theorem which relates the sides of the triangle. It is expressed as follows:
c^2 = a^2 + b^2
where c is the hypotenuse or the longest side and a, b are the two shorter sides.
To prove that the triangle is indeed a right triangle, we use the equation above.
c^2 = a^2 + b^2
c^2 = 20^2 = 10^2 + (10sqrt(3))^2
400 = 100 + (100(3))
400 = 400
Sum = (-3) + (-6) = -9
Yards gained are positive, and yards lost are negative.
If you lose 3 yards on one play and 6 yards on another, you have lost a total of 9 yards.
Answer:
12y+9
Step-by-step explanation: