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Alexus [3.1K]
3 years ago
6

Betsy recently assumed an information security role for a hospital located in the United States. What compliance regulation appl

ies specifically to healthcare providers?
a. FFIEC
b. FISMA
c. HIPAA
d. PCI DSS
Computers and Technology
1 answer:
IceJOKER [234]3 years ago
7 0

HIPAA compliance regulation applies specifically to healthcare providers

c. HIPAA

<u>Explanation:</u>

HIPAA stands for Health Insurance Portability and Accountability Act. HIPAA applies to specifically to healthcare providers.

It is a law which was designed to provide privacy standards to protect the patient's medical records, reports and other health information which may be sensitive or confidential provided to health plans, doctors, hospitals and other health care providers.

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What is the output of doublec= 12.0 / 5 Systemoutprintln (c)
artcher [175]

Answer:

The code will produce:-

2.4

Explanation:

In this code the result of the arithmetic operation is stored in the variable c.On evaluating the expression it divides 12.0 by 5 which results in 2.4 and it is stored in float variable c.Then it is printed on the screen using print statement.Since the c is double variable so the result will be a decimal number.

Hence the answer is 4.

6 0
3 years ago
Which of the following are reasons why it is important to properly recycle electronic equipment? Select all that apply.
faltersainse [42]
I think it is C. Sorry if I am wrong
4 0
3 years ago
Read 2 more answers
Two communicating devices are using a single-bit even parity check for error detection. The transmitter sends the byte 10101010
icang [17]

Answer:

The receiver will not detect the error.

Explanation:

The byte sent by transmitter: 10101010

The byte received by receiver due to channel noise: 10011010

If you see the bold part of the both sent and received bytes you can see that the number of bits changed is 2.

The two communicating devices are using a single-bit even parity check. Here there are two changed bits so this error will not be detected as this single bit even parity check scheme has a limit and it detects the error when the value of changed bit is odd but here it is even.

This parity scheme basically works well with the odd number of bit errors.

7 0
3 years ago
Type (dog, cat, budgie, lizard, horse, etc.) Create a class that keeps track of the attributes above for pet records at the anim
Alenkinab [10]

Answer:

If you did the exercise with two Dog objects, it was a bit boring, right? After all, we have nothing to separate the dogs from each other and no way of knowing, without looking at the source code, which dog produced which bark.

In the previous article, I mentioned that when you create objects, you call a special method called a constructor. The constructor looks like the class name written as a method. For example, for a Dog class, the constructor would be called Dog().

The special thing about constructors is that they are the path to any new object, so they are a great place to call code that initializes an object with default values. Further, the return value from a constructor method is always an object of the class itself, which is why we can assign the return value of the constructor to a variable of the type of class we create.

However, so far, we have not actually created a constructor at all, so how come we can still call that method?

In many languages, C# included, the language gives you a free and empty constructor without you having to do anything. It is implied that you want a constructor; otherwise there would be no way of using the class for anything, so the languages just assume that you have written one.

This invisible and free constructor is called the default constructor, and, in our example, it will look like this:

public Dog(){ }

Notice that this syntax is very similar to the Speak() method we created earlier, except that we do not explicitly return a value nor do we even declare the return type of the method. As I mentioned earlier, a constructor always returns an instance of the class to which it belongs.

In this case, that is the class Dog, and that is why when we write Dog myDog = new Dog(), we can assign the new object to a variable named myDog which is of type Dog.

So let’s add the default constructor to our Dog class. You can either copy the line above or, in Visual Studio, you can use a shortcut: type ctor and hit Tab twice. It should generate the default constructor for you.

The default constructor doesn’t actually give us anything new because it is now explicitly doing what was done implicitly before. However, it is a method, so we can now add content inside the brackets that will execute whenever we call this constructor. And because the constructor runs as the very first thing in an object’s construction, it is a perfect place to add initialization code.

For example, we could set the Name property of our objects to something by adding code such as this:

public Dog()

{

   this.Name = "Snoopy";

}

This example will set the Name property of any new objects to “Snoopy”.

Of course, that’s not very useful because not all dogs are called “Snoopy”, so instead, let us change the method signature of the constructor so that it accepts a parameter.

The parentheses of methods aren’t just there to look pretty; they serve to contain parameters that we can use to pass values to a method. This function applies to all methods, not just constructors, but let’s do it for a constructor first.

Change the default constructor signature to this:

public Dog(string dogName)

This addition allows us to send a string parameter into the constructor, and that when we do, we can refer to that parameter by the name dogName.

Then, add the following line to the method block:

this.Name = dogName;

This line sets this object’s property Name to the parameter we sent into the constructor.

Note that when you change the constructor’s signature, you get a case of the red squigglies in your Program.cs file.When we add our own explicit constructors, C# and .NET will not implicitly create a default constructor for us. In our Program.cs file, we are still creating the Dog objects using the default parameter-less constructor, which now no longer exists.

To fix this problem, we need to add a parameter to our constructor call in Program.cs. We can, for example, update our object construction line as such:

Dog myDog = new Dog(“Snoopy”);

Doing so will remove the red squigglies and allow you to run the code again. If you leave or set your breakpoint after the last code line, you can look at the Locals panel and verify that your object’s Name property has indeed been? Got it?

5 0
2 years ago
Write a program that has a conversation with the user. The program must ask for both strings and numbers as input. The program m
konstantin123 [22]

Answer:

yo im sorry eat my cookie

Explanation

doorkoeeworkwoeroewkrwerewrwe

5 0
3 years ago
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