Question

Find the volume for the regular pyramid. slant height = 6, length of side = 4

Answer 1

V = 1/3 · 6 · a²√3 / 4 · h
a = 4;
h² = 6² - ( 4√3/2 )²
h² = 36 - 11.999 = 24.001
h = √ 24.001 = 4.8989 ≈ 4.9 
V = 1/3 · 6 · 16√3 / 4 · 4.9 = 39.2√3 = 67.9