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Elenna [48]
3 years ago
14

21. Find the measures of the numbered angles.

Mathematics
2 answers:
mixas84 [53]3 years ago
8 0
1 , 2, 3 are 76 and 4 is 104 .
rodikova [14]3 years ago
5 0

Answer:

1: 76°

2: 76°

3: 104°

4: 76°

Step-by-step explanation:

1: 76°

2: 76°

3: 104°

4: 76°

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3 3/11

Step-by-step explanation:

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Which of the following equations is parallel to the line y = 3x + 1 and passes through the point (6, –3)?
MA_775_DIABLO [31]
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3 years ago
Solve x^2+20x+100=50
uysha [10]
1. You con solve the quadratic equation x^2+20x+100=50<span> by following the proccedure below:
 
 2. Pass the number 50 from the right member to the left member. Then you obtain:
 
 x^2+20x+100-50=0
</span><span> x^2+20x+50=0
</span><span> 
 3. Then, you must apply the quadratic equation, which is:
 
 x=(-b±√(b^2-4ac))/2a
 
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</span><span> 
 a=1
 b=20
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6 0
3 years ago
Consider the two expressions 4b(b+1) and (2b+7)(2b-8). Compare their values if b=-3, b=-2, and if b=10. Is it true that for an v
frutty [35]

Answer:

FIRST EXPRESSION:

-  If b=-3, the value of 4b(b+1) is  24

-  If b=-2, the value of 4b(b+1) is  8

- If b=10, the value of 4b(b+1) is  440

 SECOND EXPRESSION:

-  If b=-3, the value of (2b+7)(2b-8)) is  -14

-  If b=-2, the value of (2b+7)(2b-8)) is  -36

- If b=10, the value of (2b+7)(2b-8)) is  324

Yes, for any value of "b" the value of the first expression is greater than the value of the second expression.

Step-by-step explanation:

Substitute the given values of "b" into each expression and evaluate.

- For the first expression 4b(b+1), you get:

If b=-3 → 4(-3)(-3+1)=24

If b=-2 → 4(-2)(-2+1)=8

 If b=10 → 4(10)(10+1)=440

 - For the second expression (2b+7)(2b-8)), you get:

If b=-3 → (2(-3)+7)(2(-3)-8)=-14

If b=-2 → (2(-2)+7)(2(-2)-8)=-36

 If b=10 → (2(10)+7)(2(10)-8)=324

You can observe that for any value of "b" the value of the first expression is greater than the value of the second expression.

7 0
3 years ago
8 x plus 2y equal 7?​
juin [17]

Answer:

8x+2y=68

If this doesn't answer your question, please comment so that I can help you.

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