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3 years ago

Do u understand? I will mark a brainlist

Mathematics

1 answer:

horsena [70]3 years ago

8 0

Answer:

Step-by-step explanation:

4g(3)+2[g(2)]²

4((3+4)/√7(3)-5)+2[(2+4)/√7(2)-5]²

=15

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One step equations, solve:<br> -6=y+2

Pavel [41]

Well I don’t know if you want to know how to solve it but y = -8

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3 years ago

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Round 3489 to nearest thousand

Anastaziya [24]

Your answer is 3,000.

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3 years ago

Maths very easy class 8

Aleks04 [339]

Answer:

Rs. 333

Step-by-step explanation:

Area of the surface of the cuboidal box to be painted = surface area of the cuboidal box - area of the base

✔️Surface area of the cuboidal box = 2(L*W + W*H + L*H)

L = 6 cm

W = 4 cm

H = 2.5 cm

Surface area of the cuboidal box = 2(6*4 + 4*2.5 + 6*2.5) = 2(24 + 10 + 15) = 2(49)

Surface area of cuboidal box = 98 cm²

✔️Area of base = L*W

= 6*4 = 24 cm²

Area of the cuboidal box to be painted = 98 - 24 = 74 cm²

✔️Cost of painting 74 cm² at Rs. 4.50 per cm² = 74 × 4.50 = Rs. 333

8 0

3 years ago

For the function given below, find a formula for the Riemann sum obtained by dividing the interval [0,5] into n equal subinterva

sergij07 [2.7K]

Given

we are given a function

$f(x)=x^2+5$

over the interval [0,5].

Required

we need to find formula for Riemann sum and calculate area under the curve over [0,5].

Explanation

If we divide interval [a,b] into n equal intervals, then each subinterval has width

$\Delta x=\frac{b-a}{n}$

and the endpoints are given by

$a+k.\Delta x,\text{ for }0\leq k\leq n$

For k=0 and k=n, we get

$\begin{gathered} x_0=a+0(\frac{b-a}{n})=a \\ x_n=a+n(\frac{b-a}{n})=b \end{gathered}$

Each rectangle has width and height as

$\Delta x\text{ and }f(x_k)\text{ respectively.}$

we sum the areas of all rectangles then take the limit n tends to infinity to get area under the curve:

$Area=\lim_{n\to\infty}\sum_{k\mathop{=}1}^n\Delta x.f(x_k)$

Here

$f(x)=x^2+5\text{ over the interval \lbrack0,5\rbrack}$ $\Delta x=\frac{5-0}{n}=\frac{5}{n}$ $x_k=0+k.\Delta x=\frac{5k}{n}$ $f(x_k)=f(\frac{5k}{n})=(\frac{5k}{n})^2+5=\frac{25k^2}{n^2}+5$

Now Area=

$\begin{gathered} \lim_{n\to\infty}\sum_{k\mathop{=}1}^n\Delta x.f(x_k)=\lim_{n\to\infty}\sum_{k\mathop{=}1}^n\frac{5}{n}(\frac{25k^2}{n^2}+5) \\ =\lim_{n\to\infty}\sum_{k\mathop{=}1}^n\frac{125k^2}{n^3}+\frac{25}{n} \\ =\lim_{n\to\infty}(\frac{125}{n^3}\sum_{k\mathop{=}1}^nk^2+\frac{25}{n}\sum_{k\mathop{=}1}^n1) \\ =\lim_{n\to\infty}(\frac{125}{n^3}.\frac{1}{6}n(n+1)(2n+1)+\frac{25}{n}n) \\ =\lim_{n\to\infty}(\frac{125(n+1)(2n+1)}{6n^2}+25) \\ =\lim_{n\to\infty}(\frac{125}{6}(1+\frac{1}{n})(2+\frac{1}{n})+25) \\ =\frac{125}{6}\times2+25=66.6 \end{gathered}$

So the required area is 66.6 sq units.

3 0

1 year ago

At an ice cream store, a family ordered 3 banana splits and 3 hot fudge sundaes, paying a total of $21 for their order. The next

STALIN [3.7K]

Answer:

Banana split = $3

Hot fudge sundaes = $4

Step-by-step explanation:

please make me brainliest :)

5 0

3 years ago